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Rainbow [258]
3 years ago
11

The model at the right best represents what percent?

Mathematics
2 answers:
leva [86]3 years ago
8 0

Answer:

65% out of 100%

Step-by-step explanation:

hope this helps! :)

Drupady [299]3 years ago
5 0

Answer:

hehe ily tacos hehehhee

Step-by-step explanation:

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Expand it <br> (2/7z -3/5x)2
svet-max [94.6K]
( 2 / 7 z - 3 / 5 x ) 2
3 0
3 years ago
Find the roots of h(t) = (139kt)^2 − 69t + 80
Sonbull [250]

Answer:

The positive value of k will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80, roots are those values of t so that h(t) = 0. That is:

19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0 (1)

Roots are determined analytically by the Quadratic Formula:

t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}

t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }

The smaller root is t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }, and the larger root is t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }.

h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80 has one real root when \frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0. Then, we solve the discriminant for k:

\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}

k \approx \pm 0.028

The positive value of k will result in exactly one real root is approximately 0.028.

7 0
2 years ago
Consider the following table does this represent a function why or why not?
NARA [144]
This doesn't represent an function. Because the output is uneven to the other outputs,
1=4, 2=7 if you divided 2 into 2 parts it would equal 1=3.5 not 4.
8 0
3 years ago
There are 20 players in a table tennis competition. each player must play exactly one match against every other player. how many
Flauer [41]
There are 10 matches in the competition if you count every other player you'll end up with 10

7 0
3 years ago
Multiply and simplify: b3 • b • b4 • b2
Luden [163]
Are those supposed to be exponents? When multiplying exponents you add them together

b^3 * b^1 * b^4 * b^2  
3 + 1 + 4 + 2 = 10

Answer: b^10
5 0
3 years ago
Read 2 more answers
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