Question

Two cars collide at an intersection. One car has a mass of 1600 kg and is

Answer 1

The combined momentum is 4000 kg m/s south

Explanation:

The total combined momentum of the two cars is given by the vector addition of the momenta of the two cars.

For this problem, we choose north as positive direction and south as negative direction.

The momentum of the first car travelling north is given by:

$p_1 = m_1 v_1$

where

$m_1 = 1600 kg$ is the mass of the car

$v_1 = +8 m/s$ is its velocity

Substituting,

$p_1 = (1600)(8)=+12800 kg m/s$

The momentum of the second car travelling south is given by:

$p_2 = m_2 v_2$

where

$m_2 = 1400 kg$ is the mass of the car

$v_2= -12 m/s$ is its velocity (negative because the car travels south)

Substituting,

$p_2 = (1400)(-12)=-16800 kg m/s$

And therefore, the combined momentum is

$p=p_1 + p_2 = +12800 + (-16800)=-4000 kg m/s$

where the negative sign means the direction of the total momentum is south.

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