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Sav [38]
3 years ago
12

Two cars collide at an intersection. One car has a mass of 1600 kg and is

Physics
1 answer:
pickupchik [31]3 years ago
4 0

The combined momentum is 4000 kg m/s south

Explanation:

The total combined momentum of the two cars is given by the vector addition of the momenta of the two cars.

For this problem, we choose north as positive direction and south as negative direction.

The momentum of the first car travelling north is given by:

p_1 = m_1 v_1

where

m_1 = 1600 kg is the mass of the car

v_1 = +8 m/s is its velocity

Substituting,

p_1 = (1600)(8)=+12800 kg m/s

The momentum of the second car travelling south is given by:

p_2 = m_2 v_2

where

m_2 = 1400 kg is the mass of the car

v_2= -12 m/s is its velocity (negative because the car travels south)

Substituting,

p_2 = (1400)(-12)=-16800 kg m/s

And therefore, the combined momentum is

p=p_1 + p_2 = +12800 + (-16800)=-4000 kg m/s

where the negative sign means the direction of the total momentum is south.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

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Find the magnitude of the free-fall acceleration at the orbit of the Moon (a distance of 60RE from the center of the Earth with
Ede4ka [16]

Answer:

The magnitude of the free-fall acceleration at the orbit of the Moon is 2.728\times 10^{-3}\,\frac{m}{s^{2}} (\frac{2.784}{10000}\cdot g, where g = 9.8\,\frac{m}{s^{2}}).

Explanation:

According to the Newton's Law of Gravitation, free fall acceleration (g), in meters per square second, is directly proportional to the mass of the Earth (M), in kilograms, and inversely proportional to the distance from the center of the Earth (r), in meters:

g = \frac{G\cdot M}{r^{2}} (1)

Where:

G - Gravitational constant, in cubic meters per kilogram-square second.

M - Mass of the Earth, in kilograms.

r - Distance from the center of the Earth, in meters.

If we know that G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}, M = 5.972\times 10^{24}\,kg and r = 382.26\times 10^{6}\,m, then the free-fall acceleration at the orbit of the Moon is:

g = \frac{\left(6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}} \right)\cdot (5.972\times 10^{24}\,kg)}{(382.26\times 10^{6}\,m)^{2}}

g = 2.728\times 10^{-3}\,\frac{m}{s^{2}}

6 0
3 years ago
How long does it take an airplane to fly 1200 miles if it maintains a speed of 300 miles per hour
sdas [7]

Answer:

The answer is

<h2>4 hrs</h2>

Explanation:

To find the time taken we use the formula

t =  \frac{d}{v}  \\

where

d is the distance covered

v is the velocity

t is the time

From the question

d = 1200 miles

v = 300 mi/hr

We have

t =  \frac{1200}{300}  =  \frac{12}{3}  \\

We have the final answer as

<h3>4 hrs</h3>

Hope this helps you

5 0
3 years ago
if it is known that the toggle clamp is a machine, what assumptions can be made about it? check all that apply. (you must provid
muminat

A toggle clamp is a device that you employ, often but not exclusively as part of a production process, to firmly place components or parts in place.

Explain about toggle clamp.

A toggle clamp's main characteristics are its rapid action and ability to be easily turned on and off by an operator. Toggle clamps also lock in place firmly. Because of this, toggle clamps are frequently employed in production lines where components need to be held firmly and quickly removed during routine manufacturing procedures.

Toggle clamps with standard or light action are often constructed from components of pressed steel that have been zinc-plated.

Depending on the setting in which you work, Stainless Steel is another alternative for Toggle Clamp production. Stainless steel toggle clamps are frequently used in regulated areas where hygiene is crucial, such as the food industry and the pharmaceutical business.

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7 0
1 year ago
Suppose the initial kinetic energy and final potential energy in an experiment are both zero. What can you conclude? A. The fina
My name is Ann [436]

Answer:

C. The final kinetic energy is equal to the initial potential energy.

Explanation:

Based on the Principle of energy conservation:

Sum of the Initial Energy = Sum of the Final Energy

Initial Kinetic Energy + Initial Potential Energy = Final Kinetic Energy + Final Potential Energy..........(1)

Since according to the question:

Initial Kinetic Energy = 0

Final Potential Energy = 0

The equation (1) above reduces to

Initial Potential Energy = Final Kinetic Energy

8 0
2 years ago
Suppose a grower sprays (8.2x10^1) kg of water at 0 °C onto a fruit tree of mass 180 kg. How much heat is released by the water
____ [38]

Since there is no temperature change which drives heat flow, thus no heat will be released by the water.

<h3>Heat released by the water when it freezes</h3>

The heat released by the water when it freezes is calculated as follows;

Q = mcΔФ

where;

  • m is mass of water
  • c is specific heat capacity of water
  • ΔФ is change in temperature = Фf - Фi

when water freezes, the temperature, Фf = 0 °C

Q = 82 x 4200 x (0 - 0)

Q = 0

Since there is no temperature change which drives heat flow, thus no heat will be released by the water.

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6 0
2 years ago
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