All categories

2 years ago

A 06-C charge and a 07-C charge are apart at 3 m apart. What force attracts them?

Physics

1 answer:

Vlad [161]2 years ago

5 0

Answer:

Force of 37.8 × 10^(6) N attracts the two charges

Explanation:

The force between two charges is given by

F = k*q1*q2/r²

Where q1 and q2 are 0.06 C and 0.07 C.

r is the distance between q1 and q2 which is equal to 3 m

k is a constant = 9 × 10^(9) N.m²/C²

F = (9 × 10^(9) × 0.06 × 0.07)/3²

F = 37.8 × 10^(6) N

You might be interested in

Glycerin is poured into an open U-shaped tube until the height in both sides is 20cm. Ethyl alcohol is then poured into one arm

Liula [17]

Answer:

7.5 cm

Explanation:

In the figure we can see a sketch of the problem. We know that at the bottom of the U-shaped tube the pressure is equal in both branches. Defining $\rho_A:$ Ethyl alcohol density and $\rho_G:$ Glycerin density , we can write:

$\rho_A\times g \times h_1 + \rho_G \times g \times h_2 = \rho_G \times g \times h_3$

Simplifying:

$\rho_A\times h_1 = \rho_G \times (h_3 - h_2) (1)$

On the other hand:

$h_1 + h_2 = \Delta h + h_3$

Rearranging:

$h_1 - \Delta h = h_3 - h_2 (2)$

Replacing (2) in (1):

$\rho_A\times h_1 = \rho_G \times (h_1 - \Delta h)$

Rearranging:

$\frac{h_1 \times (\rho_A - \rho_G)}{- \rho_G} = \Delta h$

Data:

$h_1 = 20 cm; \rho_A = 0.789 \frac{g}{cm^3}; \rho_G = 1.26 \frac{g}{cm^3}$

$\frac{20 cm \times (0.789 - 1.26) \frac{g}{cm^3}}{- 1.26\frac{g}{cm^3}} = \Delta h$

$7.5 cm = \Delta h$

7 0

3 years ago

Which of the following statements are true about magnets?

timama [110]

The correct answer is 3

4 0

2 years ago

Convert time from 12-hour to 24-hour clock.

Kamila [148]

22:54 is the answer you are looking for

6 0

2 years ago

<img src="https://tex.z-dn.net/?f=2.25%20%5Ctimes%2030" id="TexFormula1" title="2.25 \times 30" alt="2.25 \times 30" align="absm

Paraphin [41]

67.5 is the answer i believe!!

7 0

2 years ago

Read 2 more answers

What is the gravity force between two stars with mass of 5,000,000 kg and 1,000,000 kg if the distance between them is 100 m

Luda [366]

Answer:

0.0334N

Explanation:

Given parameters:

M1 = 5 x 10⁶kg

M2 = 1 x 10⁶kg

Distance = 100m

Unknown:

Gravitational force = ?

Solution:

To solve this problem, we use the Newton's law of universal gravitation.

Fg = $\frac{G m1 m2}{r^{2} }$

G is the universal gravitation constant

m is the mass

r is the distance

Fg = $\frac{6.67 x 10^{-11} x 5 x 10^{6} x 1 x 10^{6} }{100^{2} }$ = 0.0334N

8 0

2 years ago

A 06-C charge and a 07-C charge are apart at 3 m apart. What force attracts them?​

A 06-C charge and a 07-C charge are apart at 3 m apart. What force attracts them?