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padilas [110]
3 years ago
14

Question 11 (5 points)

Chemistry
1 answer:
LenKa [72]3 years ago
8 0

Answer:

False

Explanation:

On the left side of the equation (Li + O2), there is 1 Li atom and 2 O atoms.

but on thw right side of the equation (Li2O,) there is 2 Li atoms and 1 O atom

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What is the percentage of s-character in an sp hybrid? O 25% 50% o 75% O 66%
marishachu [46]

Answer: 50%

Explanation:

The number of electron pairs are 2 for hybridization to be sp and the electronic geometry of the molecule will be linear.

1. percentage of s character in sp hybrid orbital =\frac{\text {number of s orbitals}}{\text {total number of orbitals}}=\frac{1}{2}\times 100=50\%

2. percentage of s character in sp^2 hybrid orbital =\frac{\text {number of s orbitals}}{\text {total number of orbitals}}=\frac{1}{3}\times 100=33.3\%

3. percentage of s character in sp^3 hybrid orbital =\frac{\text {number of s orbitals}}{\text {total number of orbitals}}=\frac{1}{4}\times 100=25\%

Thus percentage of s-character in an sp hybrid is 50%.

8 0
3 years ago
How many particles are in 2.0 moles of CH4
Whitepunk [10]

Answer: There are 4.8 x 1024 hydrogen atoms in 2.0 moles of CH4

6 0
2 years ago
Read 2 more answers
What would be the freezing point of a solution that has a molality of 1.324 m which was prepared by dissolving biphenyl (C12H10)
lbvjy [14]

The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.

A solution is prepared by dissolving biphenyl into naphthalene. We can calculate the freezing point depression (ΔT) for naphthalene using the following expression.

\Delta T = i \times Kf \times m =   1 \times 6.90 \°C/m  \times 1.324m = 9.14  \°C

where,

  • i: van 't Hoff factor (1 for non-electrolytes)
  • Kf: cryoscopic constant
  • m: molality

The normal freezing point of naphthalene is 80.26 °C. The freezing point of the solution is:

T = 80.26 \° C - 9.14 \° C = 71.12 \° C

The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.

Learn more: brainly.com/question/2292439

3 0
3 years ago
Name the functional group in the
8_murik_8 [283]
It’s called Diethyl ether so I think the answer is D
8 0
3 years ago
What is the molarity if I take 10mL of 20 volumes Hydrogen Peroxide?
Kryger [21]

Answer:

1.635 M

Explanation:

Given:

10 mL of 20 volumes Hydrogen Peroxide

Here,

20 volumes of Hydrogen Peroxide means that on decomposition of 1 mL of H₂O₂ 20 mL of O₂ is obtained

also,

means 1 dm³ of H₂O₂ solution produces 20 dm³ oxygen

Now,

at 298K and 1 atm

20 dm³ oxygen = \frac{\textup{20}}{\textup{24.47}}  moles

or

= 0.817 moles

also,

2H₂O₂ → 2H₂O + O₂

thus,

1 dm³ of solution must contain 2 × moles of O₂ as moles of H₂O₂

thus,

Number of moles of H₂O₂ = 2 × 0.817

or

Number of moles of H₂O₂  = 1.635 moles

Hence,

For 20 volume hydrogen peroxide is 1.635 M

3 0
3 years ago
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