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padilas [110]
3 years ago
14

Question 11 (5 points)

Chemistry
1 answer:
LenKa [72]3 years ago
8 0

Answer:

False

Explanation:

On the left side of the equation (Li + O2), there is 1 Li atom and 2 O atoms.

but on thw right side of the equation (Li2O,) there is 2 Li atoms and 1 O atom

You might be interested in
What are three reasons that using renewable energy is important.
wariber [46]

Answer:

1. they reduce green house gases

2. they can last a long time and come back pretty much every year and some never run out

3. we have unlimited supply of most if not all renewable resources

Explanation:

hope this helps!

5 0
2 years ago
Without using Appendix B, predict the sign of ΔS° for(b) KBr(s)→ KBr(aq)
Volgvan

Since the sign is positive, the entropy increased by 88.48 J/K.

Examine the phases of the species present to determine whether a physical or chemical process will cause an increase or decrease in entropy. Keep in mind "Silly Little Goats" to aid you in telling.

[1 Sf K+1 + 1 Sf Br-1 (aq)] ([1Sf(KBr (s))])

[1(102.5) + 1(82.42)] - [1(96.44)] = 88.48 J/K

If the entropy has grown, we say that Delta S is positive, and if it has dropped, we say that Delta S is negative. Due to its ionic nature, KBr is soluble in water and causes the 'K(+)' ions to hydrate.

Learn more about Entropy here-

brainly.com/question/13146879

#SPJ4

8 0
1 year ago
You have a graduated cylinder with 10 mL of water in it.
Law Incorporation [45]

Answer:

<h3>The answer is 10 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 300 g

volume = final volume of water - initial volume of water

volume = 40 - 10 = 30 mL

We have

density =  \frac{300}{30}  =    \frac{30}{3}  \\

We have the final answer as

<h3>10 g/mL</h3>

Hope this helps you

5 0
3 years ago
Calculate the Molarity when a 6.11 mL solution of 0.1 H2SO4 is diluted with 105.12 mL of water
barxatty [35]

Molarity after dilution : 0.0058 M

<h3>Further explanation </h3>

The number of moles before and after dilution is the same  

The dilution formula

 M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution  

V₁ = volume of the solution before dilution  

M₂ = Molarity of the solution after dilution  

V₂ = Molarity volume of the solution after dilution

M₁=0.1 M

V₁=6.11

V₂=105.12

\tt M_2=\dfrac{M_1.V_1}{V_2}=\dfrac{0.1\times 6.11}{105.12}=0.0058~M

5 0
3 years ago
Khjgjhgfmhgxfhkugfdnhmvngchnvnhvhgh
igor_vitrenko [27]

Answer:

I don’t know

Explanation:

5 0
3 years ago
Read 2 more answers
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