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frosja888 [35]
4 years ago
13

What does the electron sea model for metals suggest? A. valence electrons drift freely around the metal anions B. valence electr

ons are anchored to specific metal cations C. valence electrons drift freely around the metal cations D. electrons idle around the metal cations E. valence electrons are anchored to specific metal anions
Chemistry
2 answers:
Ainat [17]4 years ago
5 0

The electron sea model for metals suggest that the valence electrons drift freely around the metal cations.

Answer: B

Explanation

The sea model of electron is used for describing the mechanism of metallic bonding.

The metallic bonding generally occurs between 2 or more metals leading to the formation of alloys.

According to electron sea model, the electrons which contributes to the metallic bond are mostly the valence electrons of the atoms, these valence electrons get de-localized and can move freely around the nuclei of other atoms.

Overall, it seems like nuclei of positive charge is surrounded by sea of negative electrons.  

ratelena [41]4 years ago
3 0

Answer-   The correct option among all the options given is option C .

Explanation- Electron sea model is named because there are more than half of the periodic table covered by metals and the way they react among themselves is completely different from the way they react with other members of the group.

Valence electrons  that are present in metals in such cases such electrons are free to roam about and drift about cations.

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During the combustion of NH3, there is an increase in the amount of oxygen present, from 5 to 20 moles while the amount of NH3 r
borishaifa [10]

Explanation:

The ratio of NH3 to NO produced will remain constant since NH3 is the limiting reactant.

Here in this reaction for every 4 moles of ammonia and 5 moles of oxygen gas , 4 moles of NO and 6 moles of water are formed.

So when the amount of oxygen gas is increased to 20 moles without changing the amount of ammonia , the amount of NO formed does not increase as ammonia becomes the limiting reactant.

6 0
3 years ago
Can someone solve this problem 5
Westkost [7]

Answer:

2

Step-by-step explanation:

A. Moles before mixing

<em>Beaker I: </em>

Moles of H⁺ = 0.100 L × 0.03 mol/1 L

                   = 3 × 10⁻³ mol

<em>Beaker II: </em>

Beaker II is basic, because [H⁺] < 10⁻⁷ mol·L⁻¹.

        H⁺][OH⁻] = 1 × 10⁻¹⁴   Divide each side by [H⁺]

             [OH⁻] = (1 × 10⁻¹⁴)/[H⁺]

             [OH⁻] = (1 × 10⁻¹⁴)/(1 × 10⁻¹²)

             [OH⁻] = 0.01 mol·L⁻¹

Moles of OH⁻ = 0.100 L × 0.01 mol/1 L

                      = 1 × 10⁻³ mol

B. Moles after mixing

                 H⁺    +    OH⁻   ⟶ H₂O

I/mol:      3 × 10⁻³   1 × 10⁻³

C/mol:   -1 × 10⁻³  -1 × 10⁻³

E/mol:    2 × 10⁻³          0

You have more moles of acid than base, so the base will be completely neutralized when you mix the solutions.

You will end up with 2 × 10⁻³ mol of H⁺ in 200 mL of solution.


C. pH

 [H⁺] = (2 × 10⁻³ mol)/(0.200 L)

        = 1 × 10⁻² mol·L⁻¹

 pH = -log[H⁺ ]

       = -log(1 × 10⁻²)

       = 2

6 0
3 years ago
A geochemist measures the concentration of salt dissolved in Lake Parsons and finds a concentration of 21.0 gL⁻¹. The geochemist
dedylja [7]

Answer:

The percentage of Lake Parsons which has evaporated since it became isolated is 68.24%.

Explanation:

The concentration of salt dissolved in Lake Parson = 21.0 g/L

= In 1 L of lake Parson  water = 21.0 g of salt

The concentration of salt in several nearby non-isolated lakes = 6.67  g/L

The salt concentration in Lake Parsons before it became isolated = 6.67 g/L

In 1 L of lake water = 6.67 g of salt

If 1 L of lake Parson  water has 6.67 g of salt. Then 21.0 grams of salt will be in ;

\frac{1}{6.67}\times 21.0 L = 3.15 L

Water evaporated = 3.15 L - 1 L = 2.15 L

The percentage of Lake Parsons which has evaporated since it became isolated:

\frac{2.15 L}{3.15 L}\times 100=68.25\%

5 0
4 years ago
Explain the optical activity of malic acid? <br>Draw a pair of stereoisomers of malic acid.​
mr_godi [17]

Under standard temperature and pressure, the optical activity of malic acid changes in the following ways:

  1. Wavelength of light
  2. Magnitude
  3. Temperature
  4. Concentration of solvent.

<h3>What is an optical activity?</h3>

An optical activity is also referred to as optical rotation and it can be defined as the ability of a substance or chemical compound to rotate the plane of polarization of a beam of plane-polarized light that passes through it.

<h3>What is malic acid?</h3>

Malic acid refers to an organic compound (dicarboxylic acid) that is typically made by all living organisms and its molecular formula is C_4H_6O_5. Malic acid is considered to be one of the most satisfactory substances to be used when studying optical activity because of its chemical properties such as having single asymmetric carbon atoms.

Under standard temperature and pressure, the optical activity of malic acid changes in the following ways:

  1. Wavelength of light
  2. Magnitude
  3. Temperature
  4. Concentration of solvent.

<h3>The stereoisomeric forms of malic acid.​</h3>

In Science, there are two (2) stereoisomeric forms of malic acid and these include:

  • L-enantiomers
  • D-enantiomers

Read more on malic acid here: brainly.com/question/1538214

6 0
2 years ago
Which of the following includes the correct pairing of volcano and its formation? Cinder volcano; large, explosive eruptions Cin
Anarel [89]
The correct pairing of the volcano to its formation would be the composite volcano wherein it usually yields large and violent eruptions. In addition to that, composite volcanoes or also known as the stratovolcano is usually made of materials containing increasing layers of hardened lava.
4 0
3 years ago
Read 2 more answers
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