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frosja888 [35]
3 years ago
13

What does the electron sea model for metals suggest? A. valence electrons drift freely around the metal anions B. valence electr

ons are anchored to specific metal cations C. valence electrons drift freely around the metal cations D. electrons idle around the metal cations E. valence electrons are anchored to specific metal anions
Chemistry
2 answers:
Ainat [17]3 years ago
5 0

The electron sea model for metals suggest that the valence electrons drift freely around the metal cations.

Answer: B

Explanation

The sea model of electron is used for describing the mechanism of metallic bonding.

The metallic bonding generally occurs between 2 or more metals leading to the formation of alloys.

According to electron sea model, the electrons which contributes to the metallic bond are mostly the valence electrons of the atoms, these valence electrons get de-localized and can move freely around the nuclei of other atoms.

Overall, it seems like nuclei of positive charge is surrounded by sea of negative electrons.  

ratelena [41]3 years ago
3 0

Answer-   The correct option among all the options given is option C .

Explanation- Electron sea model is named because there are more than half of the periodic table covered by metals and the way they react among themselves is completely different from the way they react with other members of the group.

Valence electrons  that are present in metals in such cases such electrons are free to roam about and drift about cations.

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Nady [450]
I would say D, because the object's speed moves up, therefore accelerating. 
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Compare and contrast alpha beta and gamma radiation
Evgen [1.6K]
There are usually 3 topics used to compare types of radiation: 

Ionising ability
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Range in air

Ionising ability
Alpha radiation has strong ionising ability, while beta only has moderate ionisation and gamma is very weakly ionising.

Penetrative power 
Alpha particles are weakly penetrating, stopped by paper, while beta particles have stronger penetrating ability, stopped by skin and gamma radiation is very strongly penetrating, stopped only by thick layers of lead.

Range in air
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Hope this helps:)


8 0
3 years ago
A compound contains 6.0 g of carbon and 1.0 g of hydrogen and has a molar mass of 42.0 g/mol.
makvit [3.9K]

Answer:

%C = 85.71 wt%; %H = 14.29 wt%; Empirical Formula => CH₂; Molecular Formula => C₃H₆

Explanation:

%Composition

Wt C = 6 g

Wt H = 1 g

TTL Wt = 6g + 1g = 7g

%C per 100wt = (6/7)100% = 85.71 wt%

%H per 100wt = (1/7)100% = 14.29 wt % or, %H = 100% - %C = 100% - 85.71% = 14.29 wt% H

What you should know when working empirical formula and molecular formula problems.

Empirical Formula=> <u>smallest</u> whole number ratio of elements in a compound

Molecular Formula => <u>actual</u> whole number ratio of elements in a compound

Empirical Formula Weight x Whole Number Multiple = Molecular Weight

From elemental %composition values given (or, determined as above), the empirical formula type problem follows a very repeatable pattern. This is ...

% => grams => moles => ratio => reduce ratio => empirical ratio

for determination of molecular formula one uses the empirical weight - molecular weight relationship above to determine the whole number multiple for the molecular ratios.

Caution => In some 'textbook' empirical formula problems, the empirical ratio may contain a fraction in the amount of 0.25, 0.50 or 0.75. If such an issue arises, multiply all empirical ratio numbers containing 0.25 and/or 0.75 by '4'  to get the empirical ratio and multiply all empirical ration numbers containing 0.50 by '2' to get the final empirical ratio.

This problem:

Empirical Formula:

Using the % per 100wt values in part 'a' ...

              %     =>         grams                 =>                 moles

%C => 85.71% => 85.71 g* / 100 g Cpd => (85.71 / 12) = 7.14 mol C

%H => 14.29% => 14.29 g / 100 g Cpd => (14.29 / 1) = 14.29 mol H

=> Set up mole Ratio and Reduce to Empirical Ratio:

mole ratio C:H =>  7.14 : 14.29

<u>To reduce mole values to the smallest whole number ratio,  divide all mole values by the smaller mole value of the set.</u>

=> 7.14/7.14 : 14.29/7.14 => Empirical Ration=> 1 : 2

∴ Empirical Formula => CH₂

Molecular Formula:

(Empirical Formula Wt)·N = Molecular Wt => N = Molecular Wt / Empirical Wt

N = 42 / 14 = 3 => multiply subscripts of empirical formula by '3'.

Therefore, the molecular formula is C₃H₆

3 0
3 years ago
Which of these elements is the most reactive?<br> potassium<br> calcium<br> titanium<br> scandium
vladimir1956 [14]

Answer:

Scandium is the most reactive

3 0
3 years ago
2. Under a pressure of 95kPa and a temperature of 25 C, a gas occupies 4.0 liters. What would the new
Alekssandra [29.7K]

Answer:

35

Explanation:

multiply and subtract

3 0
3 years ago
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