Answer:
The initial velocity is 1.27 m/s.
Explanation:
distance, s = 1.8 m
acceleration, a = - 0.45 m/s^2
final velocity, v = 0
let the initial velocity is u.
Use third equation of motion
Answer:
i assume the system is in equilibrium
Explanation:
(W_p-T)(2)+W_b(2.5)= T(sin 45 degrees)(5)
T(((sin 45 degrees)(5)) + 2) = (W_p)(2) + W_b(2.5)= T(5.5355)
Answer: K/2
Rotational kinetic energy can
be expressed as: k (rotational) = 1/2 Iw2
where w is the angular velocity, I is
the moment of inertia around the axis of rotation.
K=1/2mv2
Kdrum=1/2 Iw2=1/2(1/2mR2) (v/R)2 =1/4 mv2 = 1/2K or K/2
The energy due to the rotation of an object and is part of
its total kinetic energy is called rotational kinetic energy. Things that spool without sliding have some
fraction of their energy as translational kinetic and the remainder as
rotational kinetic and looking at rotational
energy separately around an object’s axis of rotation yields the ratio that
depends on the moment of inertia of the object that is rolling.
