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Juliette [100K]
3 years ago
10

Explain how each of the fIt is close to sunset when Brandon is hiking in the woods with his dog. The dog suddenly stops walking

and starts to growl menacingly at something in the shadows of the forest. Brandon squints his eyes and tries to make out what alerted his dog. He tightens his grip on the leash and strains to hear any movement in the dry leaves. He can also feel his pulse increase, and his mouth feels very dry.ollowing concepts applies to Brandon’s current situation.
Physics
1 answer:
Agata [3.3K]3 years ago
4 0

Answer:

His fight or flight is being activated making the adrenaline go through him making him alert and ready for what's coming at him. Depending on what happens next Fight or Flight will take place. If the body feels in danger he will flee and if the body thinks it's not as big of a threat he can fight it off.

Explanation:

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Question 2.
boyakko [2]

The tensile stress of the wire supporting 2 kg mass is determined as 6.1 x 10⁷ N/m².

<h3>Tensile stress of the wire</h3>

The tensile stress of the wire is calculated as follows;

σ = F/A

where;

  • A is area of the wire

A = πr² = πD²/4

where;

  • D is diameter = 0.64 mm

A = π x (0.64 x 10⁻³)²/4

A = 3.22 x 10⁻⁷ m²

σ = F/A = (mg)/A = (2 x 9.8)/( 3.22 x 10⁻⁷)

σ = 6.1 x 10⁷ N/m²

Learn  more about tensile stress here: brainly.com/question/25748369

#SPJ1

3 0
2 years ago
[100 POINTS] Which of the following do not make their own energy through nuclear fusion? Select all that apply.
Ksenya-84 [330]

Answer:

The correct answer is :

A . Giant star

B . proto star

F .main sequence star

Explanation:

hope this helps

7 0
4 years ago
Read 2 more answers
A cart is rolling across the floor at a constant velocity of 2 m/s to the right. The cart is pushed again to the right, and it s
OlgaM077 [116]
The force of the push and acceleration of the cart are  related such as The unbalanced push causes the cart to accelerate.

4 0
3 years ago
Suppose the Sun appeared to you 900 times dimmer than it does now. How far away from the Sun would you be? (A) 1/9 AU (B) 3 AU
Harrizon [31]

Answer:

The correct answer is option 'c': 30 AUs

Explanation:

For a spherical wave front emitted by sun with total energy 'E' the energy density over the surface when it is at a distance 'r' from the sun is given by

e=\frac{E}{4\pi r^{2}}

This energy per unit area is sensed by observer as intensity of the sun.

Let the initial intensity of sun at a distance r_{1} be e_{1}

Thus if the sun becomes 900 times dimmer we have

e'=\frac{e_{1}}{900}\\\\\frac{E}{4\pi r_{2}^{2}}=\frac{1}{900}\times \frac{E}{4\pi r_{1}^{2}}\\\\\Rightarrow r_{2}^{2}={r_{1}^{2}}\times 900\\\\\therefore r_{2}={r_{1}}\times {30}

Thus the distance increases 30 times.

5 0
4 years ago
A projectile is shot directly away from Earth's surface. Neglect the rotation of the Earth.
Maksim231197 [3]

Answer:

Explanation:

We shall apply law of  conservation of mechanical energy for projectile being thrown .

Total energy on the surface = total energy at height h required

a ) At height h , velocity = .351 x ( 2 GM/R x h )

\frac{-GM}{R} + \frac{m\times(.351\times\sqrt{2GM})^2 }{2R } = \frac{-GMm}{R+h} + 0

\frac{-GMm}{R} +\frac{1}{2}\times  \frac{-2GMm}{R} \times0.123=\frac{-GMm}{R+h}

\frac{0.877GMm}{R} =\frac{-GMm}{R+h}

h = .14 R

b )

\frac{-GM}{R} + \frac{m\times(.351\times2GM) }{2R } = \frac{-GMm}{R+h} + 0

\frac{-0.649GMm}{R} = \frac{-GMm}{R+h}

h = .54 R

c ) least initial mechanical energy required at launch if the projectile is to escape Earth

= GMm / R + 1/2 m (2GM/R)

= 0

5 0
4 years ago
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