Atomic percentages<u>: 68% of copper and 32% of nickel.</u>
How this is calculated?
The given alloy is 100 g ,
m(Cu) = 0,7 · 100 g = 70 g.
m(Ni) = 0,3 · 100 g = 30 g.
n(Cu) = m(Cu) ÷ M(Cu) = 70 g ÷ 63,546 g/mol
n(Cu) = 1,10 mol.
n(Ni) = m(Ni) ÷ M(Ni) = 30 g ÷ 58,71 g/mol
n(Ni) = 0,51 mol
n(Cu) : n(Ni) = 1,10 mol : 0,51 mol
%(Cu) = 1,1 mol ÷ 1,61 mol = 0,68 = 68 %.
Similarly, %(Ni)=32%
What are Cu-Ni alloys?
- Cu-Ni alloys are alloys of copper (base metal with the largest individual content) and nickel with or without other elements, whereby the zinc content may not be more than 1%.
- When other elements are present, nickel has the largest individual content after copper, compared with each other element.
- As with other copper alloys, it is necessary to distinguish between wrought alloys, which are processed to semi-finished products, and cast alloys, from which castings are produced by various casting processes.
To know more about Cu-Ni alloys, refer:
brainly.com/question/16856761
#SPJ4
It's B, because a negative charged Ion is an anion. And since it's 1- ,one valence electron is been added to H. So it has 2 valence electrons.
Answer:
energy is used to break bonds in reactants and energy is released when new bonds form in products.The law of conservation of energy states that matter cannot be created or destroyed. Whether a chemical reaction absorbs or releases energy there is no overall change in the amount of energy during the reaction.
Explanation:
Sorry if im wrong
Answer:
Lewis structure is shown in the image below.
Explanation:
Acetate ion (CH₃COO⁻)
Valence electrons of carbon = 4
Valence electrons of oxygen = 6
Valence electrons of hydrogen = 1
Charge = 1 (Negative which means that the electrons are being added)
The total number of the valence electrons = 2(4) + 2(6) + 3(1) + 1 = 24
The Lewis structure is drawn in such a way that the octet of each atom and duet for the hydrogen in the molecule is complete. So,
The Lewis structure is shown in the image below.
Hey there!:
1 mole of FeSO4 = 151.8 g/mol
25.0 g change to mole = 25.0 / 151.8
moles of FeSO4 = 0.165 moles
One mole of any substance has 6.02*10²³ units
0.165 moles to get the number of Fe ( II ) ions :
number of Fe(II) ion = 0.165 * ( 6.02*10²³ )
number of Fe ( II ) ion = 9.93*10²² units
