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Soloha48 [4]
3 years ago
10

A 0.005 M potassium hydroxide solution is an example of what type of solution? *

Chemistry
1 answer:
poizon [28]3 years ago
7 0

Answer:

Basic solution

Explanation:

A solution containing 0.005 M potassium hydroxide has a pH of;

pOH= -log[0.005]

pOH= 2.3

But pH+pOH=14

Therefore;

pH= 14-pOH

Hence;

pH= 14-2.3= 11.7

A solution having a pH of 11.3 is clearly a basic solution because this pH indicates a substance that is basic in nature. Hence the answer given.

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this is called acid base reaction

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The small 2 next to Nitrogen is called the ____.
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atom

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Acids are __________, which means that they “eat away” at other materials. a. basic b. corrosive c. slippery d. litmus
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If 801 J of heat is available, what is the mass in grams of iron (specific heat = 0.45 J/g・°C) that can be heated from 22.5°C to
inysia [295]

Answer:

The correct answer will be "18.25 g".

Explanation:

The given values are:

Specific heat,

C = 0.45 J/g・°C

Heat involved,

q =  801 J

Temperature,

ΔT = 120.0°C-22.5°C

     = 97.5°C

As we know,

⇒  C = \frac{q}{m \Delta T}

On substituting the given values, we get

⇒  0.45=\frac{801}{m(97.5)}

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3 0
4 years ago
How much heat is required to decompose 25.5 grams of NaHCO3? 2NaHCO3(s) + 129 kJ 2Na2CO3(s) + H2O(g) + CO2(g)
Scrat [10]
The chemical equation is missbalaced.


The right balanced chemical equation is:


<span>2NaHCO3(s) + 129 kJ ---> Na2CO3(s) + H2O(g) + CO2(g)



Then, now you know that 2 moles of NaHCO3 requires 129 kJ heat, and you just need to convert 25.5 grams of NaHCO3 into number of moles to calculare the amount of heat needed.


A) Number of moles in 25.5 g of NaHCO3, n:

n = grams / molar mass


molar mass NaHCO3 = 23 g/mol + 1g/mol + 12g/mol + 3*16g/mol = 84 g/mol


n = 25.5 g / 84 g/mol = 0.304 mol


B) Heat required


Make the proportion with the theoretical ratio:


2mol / 129 kJ = 0.304 mol / x


=> x = 0.304 mol * 129 kJ / 2 mol =  19.608 kJ


Answer: 19.6 kJ
</span>
7 0
3 years ago
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