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alekssr [168]
3 years ago
9

The density of aluminum is 2.70 g/mL. If you use 108 g of aluminum foil, what is its volume in mL?

Chemistry
1 answer:
Natali5045456 [20]3 years ago
3 0

Answer:

volume =40.0 ml

Explanation:

density = mass/ volume

volume = mass/ density

volume = 108/ 2.70

volume =40.0 ml

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Why do different substances have different Odors?
mixer [17]

Answer:

Substances generate a smell when their molecules land on so-called olfactory neurones in our noses (which, for some things, is a pretty unpleasant thought). ... But this fails to explain why some molecules with similar shapes can smell completely different, while others with quite different shapes can have a similar scent.

Explanation:

I took chemistry

4 0
3 years ago
A mixture of ethyl acetate vapour and air has a relative saturation of 50% at 303 K and a total pressure of 100 kPa. If the vapo
AURORKA [14]

Answer : The correct option is, (b) 0.087

Explanation :

The formula used for relative saturation is:

\text{Relative saturation}=\frac{P_A}{P_A^o}

where,

P_A = partial pressure of ethyl acetate

P_A^o = vapor pressure of ethyl acetate

Given:

Relative saturation = 50 % = 0.5

Vapor pressure of ethyl acetate = 16 kPa

Now put all the given values in the above formula, we get:

0.5=\frac{P_A}{16kPa}

P_A=8kPa

Now we have to calculate the molar saturation.

The formula used for molar saturation is:

\text{Molar saturation}=\frac{P_{vapor}}{P_{\text{vapor free}}}

and,

P(vapor free) = Total pressure - Vapor pressure

P(vapor) = P_A = 8 kPa

So,

P(vapor free) = 100 kPa - 8 kPa = 92 kPa

The molar saturation will be:

\text{Molar saturation}=\frac{P_{vapor}}{P_{\text{vapor free}}}

\text{Molar saturation}=\frac{8kPa}{92kPa}=0.087

Therefore, the molar saturation is 0.087

5 0
3 years ago
Arranges the following molecules in order of increasing dipole moment: <br> H2O, H2S, H2Te, H2Se.
erastova [34]

Explanation:

Dipole moment is defined as the measurement of the separation of two opposite electrical charges.

H_{2}O is a bent shaped molecule with a dipole moment of 1.87.

H_{2}S is also a bent shaped molecule with a dipole moment of 1.10.

H_{2}Te is a also a bent shaped molecule and has a negligible dipole moment.

H_{2}Se has a dipole moment of 0.29.

Therefore, given molecules are arranged according to their increasing dipole moment as follows.

        H_{2}Te < H_{2}Se < H_{2}S < H_{2}O

7 0
3 years ago
How much heat will be absorbed by a 26.3 g piece of aluminum (specific heat = 0.930 J/g・°C) as it changes temperature from 23.0°
kotykmax [81]

Answer:

\boxed {\boxed {\sf 1076.196 \ Joules}}

Explanation:

Since we are given the mass, specific heat, and temperature, we should use the following formula for heat energy.

q=mc\Delta T

The mass of the aluminum is 26.3 grams. Its specific heat is 0.930 Joules per gram degree Celsius. We need to find the change in temperature.

  • The change in temperature is the difference between the initial temperature to the final temperature.
  • The temperature changes <em>from</em> 23.0°C <em>to</em> 67.0°C, so the initial is 23 degrees and the final is 67 degrees.
  • ΔT= final temperature - initial temperature
  • ΔT= 67°C - 23°C
  • ΔT= 44°C

Now we know all the values.

  • m= 26.3 g
  • c= 0.930 J/g °C
  • ΔT= 44°C

Substitute the values into the formula.

q= (26.3 \ g}) \times (0.930 \ J/g \textdegree C) \times (44 \textdegree C)

Multiply the first two numbers together. The units of grams cancel.

q= 24.459 \ J/ \textdegree C \times 44 \textdegree C

Multiply again. This time, the units of degrees Celsius cancel.

q=1076.196 \ J

<u>1076.196 Joules</u> of heat will be absorbed by the piece of aluminum.

4 0
3 years ago
Part 1
denis-greek [22]

The moles of NaOH used in the titration would be 0.00177 moles while the molarity of the vinegar will be 0.885 M

<h3>Titration calculation</h3>

Recall that: mole = molarity x volume

In this case, the molarity of the NaOH= 0.1 M

Volume of NaOH = 17.7 - 0.0 = 17.7 mL

Mole of NaOH used = 0.1 x 17.7/1000 = 0.00177 moles.

Since NaOH and vinegar have 1:1 mole ratio, the mole of vinegar will also be 0.00177 moles.

Molarity of vinegar = mole/volume = 0.00177/0.002 = 0.885 M

More on titration calculations can be found here: brainly.com/question/9226000

7 0
2 years ago
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