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3 years ago

The density of aluminum is 2.70 g/mL. If you use 108 g of aluminum foil, what is its volume in mL?

Chemistry

1 answer:

Natali5045456 [20]3 years ago

3 0

Answer:

volume =40.0 ml

Explanation:

density = mass/ volume

volume = mass/ density

volume = 108/ 2.70

volume =40.0 ml

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Why do different substances have different Odors?

mixer [17]

Answer:

Substances generate a smell when their molecules land on so-called olfactory neurones in our noses (which, for some things, is a pretty unpleasant thought). ... But this fails to explain why some molecules with similar shapes can smell completely different, while others with quite different shapes can have a similar scent.

Explanation:

I took chemistry

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3 years ago

A mixture of ethyl acetate vapour and air has a relative saturation of 50% at 303 K and a total pressure of 100 kPa. If the vapo

AURORKA [14]

Answer : The correct option is, (b) 0.087

Explanation :

The formula used for relative saturation is:

$\text{Relative saturation}=\frac{P_A}{P_A^o}$

where,

$P_A$ = partial pressure of ethyl acetate

$P_A^o$ = vapor pressure of ethyl acetate

Given:

Relative saturation = 50 % = 0.5

Vapor pressure of ethyl acetate = 16 kPa

Now put all the given values in the above formula, we get:

$0.5=\frac{P_A}{16kPa}$

$P_A=8kPa$

Now we have to calculate the molar saturation.

The formula used for molar saturation is:

$\text{Molar saturation}=\frac{P_{vapor}}{P_{\text{vapor free}}}$

and,

P(vapor free) = Total pressure - Vapor pressure

P(vapor) = $P_A$ = 8 kPa

So,

P(vapor free) = 100 kPa - 8 kPa = 92 kPa

The molar saturation will be:

$\text{Molar saturation}=\frac{P_{vapor}}{P_{\text{vapor free}}}$

$\text{Molar saturation}=\frac{8kPa}{92kPa}=0.087$

Therefore, the molar saturation is 0.087

5 0

3 years ago

Arranges the following molecules in order of increasing dipole moment: <br> H2O, H2S, H2Te, H2Se.

erastova [34]

Explanation:

Dipole moment is defined as the measurement of the separation of two opposite electrical charges.

$H_{2}O$ is a bent shaped molecule with a dipole moment of 1.87.

$H_{2}S$ is also a bent shaped molecule with a dipole moment of 1.10.

$H_{2}Te$ is a also a bent shaped molecule and has a negligible dipole moment.

$H_{2}Se$ has a dipole moment of 0.29.

Therefore, given molecules are arranged according to their increasing dipole moment as follows.

$H_{2}Te$ < $H_{2}Se$ < $H_{2}S$ < $H_{2}O$

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3 years ago

How much heat will be absorbed by a 26.3 g piece of aluminum (specific heat = 0.930 J/g･°C) as it changes temperature from 23.0°

kotykmax [81]

Answer:

$\boxed {\boxed {\sf 1076.196 \ Joules}}$

Explanation:

Since we are given the mass, specific heat, and temperature, we should use the following formula for heat energy.

$q=mc\Delta T$

The mass of the aluminum is 26.3 grams. Its specific heat is 0.930 Joules per gram degree Celsius. We need to find the change in temperature.

The change in temperature is the difference between the initial temperature to the final temperature.
The temperature changes <em>from</em> 23.0°C <em>to</em> 67.0°C, so the initial is 23 degrees and the final is 67 degrees.
ΔT= final temperature - initial temperature
ΔT= 67°C - 23°C
ΔT= 44°C

Now we know all the values.

m= 26.3 g
c= 0.930 J/g °C
ΔT= 44°C

Substitute the values into the formula.

$q= (26.3 \ g}) \times (0.930 \ J/g \textdegree C) \times (44 \textdegree C)$

Multiply the first two numbers together. The units of grams cancel.

$q= 24.459 \ J/ \textdegree C \times 44 \textdegree C$

Multiply again. This time, the units of degrees Celsius cancel.

$q=1076.196 \ J$

<u>1076.196 Joules</u> of heat will be absorbed by the piece of aluminum.

4 0

3 years ago

Part 1

denis-greek [22]

The moles of NaOH used in the titration would be 0.00177 moles while the molarity of the vinegar will be 0.885 M

<h3>Titration calculation</h3>

Recall that: mole = molarity x volume

In this case, the molarity of the NaOH= 0.1 M

Volume of NaOH = 17.7 - 0.0 = 17.7 mL

Mole of NaOH used = 0.1 x 17.7/1000 = 0.00177 moles.

Since NaOH and vinegar have 1:1 mole ratio, the mole of vinegar will also be 0.00177 moles.

Molarity of vinegar = mole/volume = 0.00177/0.002 = 0.885 M

More on titration calculations can be found here: brainly.com/question/9226000

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2 years ago