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kolbaska11 [484]

3 years ago

12

Dorrian graphed the distance, y, traveled by 2 bikes in x seconds. If the two bikes are racing a distance of 100 feet, which bik

e will win the race?

2 answers:

torisob [31]3 years ago

6 0

Answer:

The bike whose position has greater y-coordinate.

Step-by-step explanation:

If Dorrian plotted the co-ordinates of the bikes with second on the x-axis and distance traveled on the y-axis, the x-coordinates of the two bikes will be the same.

But, the bike which went faster will have the greater y-coordinate and which followed the earlier will have the smaller y-coordinate.

Hence, the bike which has greater y-coordinate will win the race.

pishuonlain [190]3 years ago

4 0

Answer:

D. Bike 1 will win because the slope of the line for Bike 1 is Three-halves, which is greater than the slope of the line for Bike 2.

Step-by-step explanation:

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Which term is a perfect square of the root 3x4?

mafiozo [28]

Answer: 9x16

Step-by-step explanation: The correct option is perfect square of 3x4 is 9x16.

3 0

3 years ago

Read 2 more answers

If f(x)=4x+3 and g(x)=x^2-3 then f(g(2))

grandymaker [24]

Answer:

<em>f(g(2))=7</em>

Step-by-step explanation:

<u>The Composite Function</u>

Given f(x) and g(x) as real functions, the composite function $(f\circ g)(x)$ is defined as:

$(f\circ g)(x)=f(g(x))$

It can be found by substituting g into f.

The given functions are:

$f(x)=4x+3$

$g(x)=x^2-3$

It's required to find f( g( 2 ) )

Find g(2):

$g(2)=2^2-3$

Operating:

$g(2)=4-3 =1$

g(2)=1

Now find f(1):

$f(1)=4(1)+3$

$f(1)=4+3 =7$

Thus:

f( g( 2 ) )=7

4 0

3 years ago

What is the slope of the function?<br> -10<br> -5<br> 5<br> 10

bixtya [17]

Answer:

m= 1/2

Step-by-step explanation:

3 0

3 years ago

Help please the question is in the photo

GarryVolchara [31]

First one (ignore22222323333333)

6 0

3 years ago

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 16x2 + y2 = 16 and the plane x + y

Yuri [45]

Let the curve C be the intersection of the cylinder

$16x^2+y^2=16$

and the plane

$x+y+z=1$

The projection of C on to the x-y plane is the ellipse

$16x^2+y^2=16$

To see clearly that this is an ellipse, le us divide through by 16, to get

$\frac{x^2}{1}+ \frac{y^2}{16}=1$

or

$\frac{x^2}{1^2}+ \frac{y^2}{4^2}=1$ ,

We can write the following parametric equations,

$x=cos(t), y=4sin(t)$

for

$0\le t \le 2\pi$

Since C lies on the plane,

$x+y+z=1$

it must satisfy its equation.

Let us make z the subject first,

$z=1-x-y$

This implies that,

$z=1-sin(t)-4cos(t)$

We can now write the vector equation of C, to obtain,

$r(t)=(cos(t),4sin(t),1-cos(t)-4sin(t))$

The length of the curve of the intersection of the cylinder and the plane is now given by,

$\int\limits^{2\pi}_0 {|r'(t)|} \, dt$

But

$r'(t)=(-sin(t),4cos(t),sin(t)-4cos(t))$

$|r'(t)|=\sqrt{(-sin(t))^2+(4cos(t))^2+(sin(t)-4cos(t))}$

$\int\limits^{2\pi}_0 {\sqrt{2sin^2(t)+32cos(t)-8sin(t)cos(t)} }\, dt=24.08778184$

Therefore the length of the curve of the intersection intersection of the cylinder and the plane is 24.0878 units correct to four decimal places.

6 0

3 years ago