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BlackZzzverrR [31]
4 years ago
14

A 500 kg empty elevator moves with a downwards acceleration of 2 m/s2. What is the tension force of the cable on the elevator? 5

000 N 4000 N 6000 N 1000 N
Physics
1 answer:
Gre4nikov [31]4 years ago
5 0

Answer:

T = 4000 N

Explanation:

We have,

Mass of an elevator, m = 500 kg

It is moving downward with an acceleration of 2\ m/s^2. It is required to find the  tension force of the cable on the elevator. We know that when the elevator is moving downward, the net force on it is given by :

F=m(g-a)

g is acceleration due to gravity

F=500\times (10-2)\\\\F=4000\ N

So, the tension force of the cable on the elevator is 4000 N.

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If a cup of coffee has temperature 95∘C95∘C in a room where the temperature is 20∘C,20∘C, then, according to Newton's Law of Coo
lina2011 [118]

Answer:

T = 76.39°C

Explanation:

given,

coffee cup temperature = 95°C

Room temperature= 20°C

expression

T( t ) = 20 + 75 e^{\dfrac{-t}{50}}

temperature at t = 0

T( 0 ) = 20 + 75 e^{\dfrac{-0}{50}}

T(0) = 95°C

temperature after half hour of cooling

T( t ) = 20 + 75 e^{\dfrac{-t}{50}}

t = 30 minutes

T( 30 ) = 20 + 75 e^{\dfrac{-30}{50}}

T( 30 ) = 20 + 75 \times 0.5488

T(30) = 61.16° C

average of first half hour will be equal to

T = \dfrac{1}{30-0}\int_0^30(20 + 75 e^{\dfrac{-t}{50}})\ dt

T = \dfrac{1}{30}[(20t - \dfrac{75 e^{\dfrac{-t}{50}}}{\dfrac{1}{50}})]_0^30

T = \dfrac{1}{30}[(20t - 3750e^{\dfrac{-t}{50}}]_0^30

T = \dfrac{1}{30}[(20\times 30 - 3750 e^{\dfrac{-30}{50}} + 3750]

T = \dfrac{1}{30}[600 - 2058.04 + 3750]

T = 76.39°C

4 0
3 years ago
Yamin is running 50 feet of No. 14 wire (with a cross section of 4,110 cmils) to a load that draws current of 11 amps. What appr
castortr0y [4]

Resistance per 1000 feet for gauge 14 wire is given as

R = 2.525 ohm

now if wire is of length 50 feet only then the resistance is given as

R = \frac{2.525}{1000}\times 50

R = 0.126 ohm

now if 11 A current flows through the wire then the voltage drop is given by ohm's law

V = iR

V = 11 \times 0.126

V = 1.4 Volts

so most appropriate answer in given options is

A. 1.8 Volts

8 0
3 years ago
explain how a maglev train provides evidence that magnetic fields can apply forces between objects that do not touch.
Furkat [3]

Answer:

Powerful electromagnets are fitted on top of guideways either ttract or repel the magents fitted on the bottom of train. The froce of attraction/repulsion rasies the train in hovering position.

Explanation:

Magentic fields exist between two opposite/like poles. The poles do not have to be touching each other. They can be separated by a distance in a medium that doesn' block magnetic field.

In magelv train the magnetic forces between two poles are used to operate the train. The two poles are separated by train body and air.

4 0
3 years ago
An object with 5 protons, 5 electrons and 6 neutrons would have what charge
Anon25 [30]

Answer:

0

Explanation:

The object would be neutral. There are equal numbers of protons and electrons, so the positive and negative charges cancel one another.

5 0
4 years ago
A 0.5 kg mass moving East with a velocity of 8 m/s is acted upon by a force of 20 N for 2.0 sec.
Andrej [43]

Answer:b

Explanation:

7 0
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