Answer:
V= 6.974 m/s
Explanation:
Component( box) weight acting parallel and down roof 88(sin39.0°)=55.4 N
Force of kinetic friction acting parallel and up roof = 18.0 N
Fnet force acting on tool box acting parallel and down roof
Fnet= 55.4 - 18.0
Fnet=37.4 N
acceleration of tool box down roof
a = 37.4(9.81)/88.0
a= 4.169 m/s²
d = 4.90 m
t = √2d/a
t= √2(4.90)/4.169
t= 1.662 s
V = at
V= 4.169(1.662)
V= 6.974 m/s
Answer:
a) 
b) 
Explanation:
The frequency of the
harmonic of a vibrating string of length <em>L, </em>linear density
under a tension <em>T</em> is given by the formula:

a) So for the <em>fundamental mode</em> (n=1) we have, substituting our values:

b) The <em>frequency difference</em> between successive modes is the fundamental frequency, since:

It is an example of rolling friction because balls roll.
Answer is ROLLING
Answer:
6g/cm³
Explanation:
Density is the mass per unit volume of any substance. To solve this problem:
Density =
Since mass = 600g
Let us find the volume;
Volume = length x width x height
Volume = 25cm x 2cm x 2cm = 100cm³
Therefore;
Density =
= 6g/cm³
Answer:
(a) 3.807 s
(b) 145.581 m
Explanation:
Let Δt = t2 - t1 be the time it takes from the moment when the motorcycle starts to accelerate until it catches up with the car. We know that before the acceleration, both vehicles are travelling at a constant speed. So they would maintain a distance of 58 m prior to the acceleration.
The distance traveled by car after Δt (seconds) at
speed is

The distance traveled by the motorcycle after Δt (seconds) at
speed and acceleration of a = 8 m/s2 is


We know that the motorcycle catches up to the car after Δt, so it must have covered the distance that the car travels, plus their initial distance:





(b)

