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4 years ago

How does the state of matter affect the speed of a sound wave traveling through it?

1 answer:

7 0

Sound travels faster through a solid or liquid than it does through a gas because the molecules are more tightly packed and allows the sound wave to travel quicker. sound is vibrations that travel through the air or other matter until it reaches someones ear which allows them to hear the sound. hope this helps

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A 0.500-kg mass suspended from a spring oscillates with a period of 1.36 s. How much mass must be added to the object to change

lord [1]

The mass that must be added is 0.628 kg

Explanation:

The period of a mass-spring system is given by

$T=2\pi \sqrt{\frac{m}{k}}$

where

m is the mass

k is the spring constant

For the initial mass-spring system in the problem, we have

m = 0.500 kg

T = 1.36 s

Solving for k, we find the spring constant:

$k=(\frac{2\pi}{T})^2 m = (\frac{2\pi}{1.36})^2 (0.500)=10.7 N/m$

In the second part, we want the period of the same system to be

T = 2.04 s

Therefore, the mass on the spring in this case must be

$m=(\frac{T}{2\pi})^2 k =(\frac{2.04}{2\pi})^2 (10.7)=1.128 kg$

Therefore, the mass that must be added is

$\Delta m = 1.128 - 0.500 = 0.628 kg$

Learn more about period:

brainly.com/question/5438962

#LearnwithBrainly

5 0

4 years ago

A 3.50-meter length of wire with a cross-sectional area of 3.14 × 10-6 meter2 is at 20° Celsius. If the wire has a resistance of

maks197457 [2]

Answer:

$5.6\times 10^{-8}\ Ohm.m$

Explanation:

Resistivity is given by $\rho=\frac {AR}{L}$ where A is cross-sectional area, R is resistance, L is the length and $\rho$ is the reistivity. Substituting 0.0625 for R, 3.14 × 10-6 for A and 3.5 m for L then the resistivity is equivalent to

$\rho=\frac {3.14\times 10^{-6}\times 0.0625}{3.5}=5.60714285714285714285714285714285714285\times 10^{-8}\approx 5.6\times 10^{-8}\ Ohm.m$

8 0

3 years ago

Solenoid 2 has twice the diameter, twice the length, and twice as many turns as solenoid 1. How does the field B2 at the center

klemol [59]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is option 3

Explanation:

From the question we are told that

The diameter of solenoid 1 is $d_1$

The length of solenoid 1 is $L_1$

The number of turns of solenoid is $N_1$

The diameter of solenoid 2 is $d_2 = 2d_1$

The length of solenoid 2 is $L_2 = 2L_1$

The number of turns of solenoid 2 is $N_2 = 2 N_1$

Generally the magnetic in a solenoid is mathematically represented as

$B = \frac{\mu_o * N * I }{L}$

From this equation we see that

$B \ \alpha \ \frac{N}{L}$

$B = C \frac{N}{L}$

Here C stands for constant

=> $C = \frac{B * \frac{L}{N}$

=> $\frac{B_1 * \frac{L_1}{N_1} = \frac{B_2 * \frac{L_2}{N_2}$

=> $\frac{B_1}{B_2 } = \frac{N_1 L _2}{ N_2L_1}$

=> $\frac{B_1}{B_2 } = \frac{N_1 * (2 L_1)}{ (2 N_2)L_1}$

=> $\frac{B_1}{B_2 } = 1$

=> $B_2 = B_1$

4 0

4 years ago

Click through the images and select the model that best shows how J.J. Thomson envisioned the atom.

Alexandra [31]

Answer:

The first one with the big plus in the middle and negatively charged electrons around.

Explanation:

7 0

3 years ago

The Bohr model of the atom addressed the problem of _____.

Ghella [55]

The Bohr model of atom addressed the problem of why electrons did not fall into the positive nucleus.

As per Rutherford's atomic model, electrons are revolving around the nucleus just like planets are revolving around the sun. But his description about electronic motion was against the Clark Maxwell's electromagnetic theory .

As per Maxwell any charged particle under accelerated motion will release energy. The electron is a negatively charged particle which under acceleration will come closer and closer to the nucleus and finally it will fall on the nucleus for which the whole atom will be destroyed. The path of electron will be a spiral one instead of circular. Hence Rutherford's theory could not explain the stability of nucleus.

Bohr addressed that electron in particular orbit has a fixed amount of energy .There will be no emission or absorption of energy as long as electron revolves around the nucleus.The electron will absorb energy when it will jump from ground state to excited state and will emit energy when it will jump from excited state to ground state.

Hence the option A is right,.

7 0

3 years ago

Read 2 more answers