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S_A_V [24]
3 years ago
8

As a person squeezes and applies pressure to the outside of a balloon air particles inside

Physics
1 answer:
MAVERICK [17]3 years ago
3 0
They will occupy less volume which will cause an increased density of the particles.
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Homework 7 Adaptive Follow-Up Problem 25.68 Item 4 Constants A cylindrical copper cable 3.30 km long is connected across a 220.0
xenn [34]

Answer:

 0.446 mm  

0.066 V/m

Explanation:

Given  

We are given the length of the copper cable L = 3.30 km and the potential difference is V = 220 V  

Solution  

(a) We want to find the diameter d of the cable when the dissipated power is P = 50W. The power consumed by the cable depends on its resistance R and it is given by equation in the form

P= V^2/R                                                (1)

Where V is the voltage in the cable. Now let us solve equation (1) for R and plug our values for V and P into equation (1) to get R  

R = V^2/P = (220)^2/(50) = 968Ω

Now we can determine the diameter of the copper wire. The resistance R of the wires depends on the area of the wire, resistivity and the length of the cable. Where equation gives us the relationship between these variables in the form  

R = pL/π*r^2                             (solve for r)

r = √pL/πR                             (2)

Now we can plug our values for Rep and L into equation (2) to get the radius of the cable where p for copper equals 1.72 x 10-8 Ω m

r =√pL/πR                    

 = √1.72 x 10-8 *3300m/968

 = 0.234 mm

Therefore, the diameter is d= 2r = 2(0.234  mm) =  0.446 mm  

(b) To determine the electric field we can use the values for the potential difference across the cable and the length of the cable, where the electric field is inversely proportional to the length of the cable as next  

E =V/L

  =220/3300m

  = 0.066 V/m

3 0
3 years ago
What is the algebraic expression for the component of the normal force in the vertical direction?
inna [77]

The algebraic expression for the component of the normal force in the vertical direction is Force= product of mass and area.

<h3>What is Force?</h3>

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction. Or, there is a specific meaning to the word "force." At this level, calling a force a push or a pull is entirely appropriate. A force is not something an object "has in it" or that it "contains." One thing experiences a force from another. There are both living things and non-living objects in the concept of a force.

To learn more about Force, visit

brainly.com/question/13014979

#SPJ4

5 0
1 year ago
Two forces whose resultant is 100newton are perpendicular to each other. If one of them makes an angle of 60newton with the resu
Elis [28]

Answer:

100 N

Explanation:

Given that,

Two forces whose resultant is 100newton are perpendicular to each other.

If one of them makes an angle of 60newton with the resultant.

F_1=100\times \sin60=86.60\ N

and

F_2=100\times \cos60=50\ N

The magnitude of force,

F=\sqrt{F_1^2+F_2^2} \\\\F=\sqrt{86.6^2+50^2} \\\\F=99.99\ N

or

F = 100 N

So, the magnitude of force is 100 N.

6 0
2 years ago
A thin metallic spherical shell of radius 0.357 m has a total charge of 5.03 times 10^-6 C placed on it. At the center of the sh
Artyom0805 [142]

Answer:

The electric field is 5.623\times10^{4}\ N/C

Explanation:

Given that,

Radius = 0.357 m

Charge Q=5.03\times10^{-6}\ C

Point charge q=4.15\times10^{-6}\ C

Distance = 0.815 m

We need to calculate the total electric field

Using formula of electric field

E=\dfrac{1}{4\pi\epsilon_{0}}\dfrac{q}{r^2}

Where, q = point charge

r = distance

Put the value into the formula

E=\dfrac{9\times10^{9}\times4.15\times10^{-6}}{(0.815)^2}

E=5.623\times10^{4}\ N/C

Hence, The electric field is 5.623\times10^{4}\ N/C

4 0
3 years ago
The air in a car tire la compressed when the car rolls over a rock. If the air
stealth61 [152]

Answer:

the signs of heat and work are; -Q and -W

Explanation:

The first law of thermodynamics is given by; ΔU = Q − W

where;

ΔU is the change in internal energy of a system,

Q is the net heat transfer (the sum of all heat transfer into and out of the system)

W is the net work done (the sum of all work done on or by the system).

Now, The system in this case is the tire and since the air gets warmer, heat must have left the system. Therefore Q is negative (-Q).

Since work is done by the system, W remains negative.

Thus, the signs of heat and work are; -Q and - W

8 0
3 years ago
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