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3 years ago

Match the following items by evaluating the expression for x = -6.

Mathematics

1 answer:

Kryger [21]3 years ago

5 0

Step-by-step explanation:

Put the value of x = -6 to all expressions:

$x^{-2}=(-6)^{-2}=\dfrac{1}{(-6)^2}=\dfrac{1}{6}\qquad\text{used}\ a^{-n}=\dfrac{1}{a^n}\\=====================\\x^{-1}=(-6)^{-1}=\dfrac{1}{(-6)^1}=-\dfrac{1}{6}\\=====================\\x^0=(-6)^0=1\qquad a^0=1\ \text{for all real numbers except 0}\\=====================\\x^1=(-6)^1=-6\qquad a^1=a\ \text{for all real numbers}\\=====================\\x^2=(-6)^2=36$

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Find the value of x.

slavikrds [6]

Answer:

$x=11$

Step-by-step explanation:

we know that

The <u><em>Midpoint Theorem</em></u> states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side.

In this problem

$(x+5)=\frac{1}{2}(3x-1)$

solve for x

Multiply by 2 both sides

$2x+10=3x-1$

subtract 2x both sides

$10=3x-1-2x$

$10=x-1$

Adds 1 both sides

$x=11$

3 0

3 years ago

If f (x) = StartRoot one-half x minus 10 EndRoot + 3, which inequality can be used to find the domain of f(x)?

just olya [345]

The inequality that represents the domain of the function is $\frac 12x - 10 \ge 0$

<h3>How to determine the domain?</h3>

The function is given as:

$f(x) = \sqrt{\frac 12x - 10} + 3$

Set the radicand greater than or equal to 0

$\frac 12x - 10 \ge 0$

Multiply through by 2

x - 20 ≥ 0

Add 20 to both sides

x ≥ 20

Hence, the domain of the function is x ≥ 20

Read more about domain at:

brainly.com/question/1770447

#SPJ1

7 0

2 years ago

Read 2 more answers

I need help ASAP on Tangent Circles!!

loris [4]

I will solve one for you to get you a idea so next u can solve all
To know whether line is tangent toa circle or not we should know that that line is a tangent line of a circle if it intersects circle at single point.
and this will always be perpendicular at radius
so in problem
1)

diameter is given 7.5
and u can see they make a right triangle ABC if that is perpendicular so segment AB is tangent to a circle.
Lets see by applying <span>Pythagorean Theorem
</span>this is method we can say that this is in fact a right triangle

a^2=b^2=c^2
a,b are shorter side c is longer side
(7.5)^2+(8)^2=(17)^2
56.25+64=289
120.25=289
both are not equal so they are not forming right triangle so segment AB is not a tangent line.

5 0

3 years ago

The numerator and denominator of a fraction are in the ratio of 3 to 5. If the numerator and denominator are both increased by 2

ivolga24 [154]

Question:

The numerator and denominator of a fraction are in the ratio of 3 to 5. If the numerator and denominator are both decreased by 2, the fraction is now equal to $\frac{1}{2}$ .