Answer:
1. A. Sour.
B. Irritating
2. A. Slippery
B. Bitter
C. Irritating
Explanation:
Acids induce salivation in the mouth which increases the bicarbonate secretions thus the sour taste. Sour taste receptors detect the hydrogen ion in the acids.
Acids may react with the fluids in the eye and thus irritate the eye cells. This is because they alter the pH of the eye fluids. Once they get into the eye they should be rinsed thoroughly with enough water and professional medical assistance sought.
Bases have a soapy feel in the skin. This is because they dissolve the fatty acids in the skin and form complexes. These complexes have a slippery feel.
The bases taste bitter in the mouth. The OH ions bind to the bitter taste receptors thus causing the bitter taste.
Once these bases get into the eyes, they alter pH of eye fluids thus causing irritation.
First, construct a balance equation for the combustion of propane. Then the 3rd equation given in the question is the formation of propane. So 1 mol of propane is formed by -104 kJ mol-1. Then, the 1st equation given in question is the formation of CO2. 3 mol of CO2 is formed so 3(-393.5). 2nd equation shows that 1 mol of H2O is formed but based on balanced equation that I constructed, 4 mol of H2O is formed so 4(-285.5). The arrows I drew was for the mathematics equation. Going to same direction of the product of combustion of propane FROM the reactant is -104 and x so I put this on the left side. Then, the remaining one is on the right side.
Answer:
1.8 × 10² cal
Explanation:
When 0.32 g of a walnut is burned, the heat released is absorbed by water and used to raise its temperature. We can calculate this heat (Q) using the following expression.
Q = c × m × ΔT
where,
c: specific heat capacity of water
m: mass of water
ΔT: change in the temperature
Considering the density of water is 1 g/mL, 58.1 mL = 58.1 g.
Q = c × m × ΔT
Q = (1 cal/g.°C) × 58.1 g × 3.1°C
Q = 1.8 × 10² cal
Answer:
C!
Explanation:
when water is boiling the water particles will give each other more space and will then be turned into a gas :)
Answer:
a)C2HBrClF3 = 197.35 g/mol
b)C12H14N2CL2 = 229.06g/mol
c)C8H10N4O2 = 194.22g/mol
d) CO(NH2)2=60.07 g/mol
e)C17H35CO2Na = 306.52 g/mol
Explanation:
Molar mass of a compound is equal to the sum of the atomic masses of the constituent elements.
a) C2HBrClF3
b) C12H14N2CL2
c) C8H10N4O2
d) CO(NH2)2
e) C17H35CO2Na