<h3>
Answer:</h3>
CdS
<h3>
Explanation:</h3>
<u>We are given;</u>
- % of cadmium is 78%
- % of sulfur is 22.0%
We are required to determine the empirical formula of cadmium sulfide
<h3>Step 1 : Determine the number of moles of Cadmium and sulfur </h3>
Assuming the mass of the cadmium sulfide is 100 g
Mass of cadmium is 78 g
Mass of sulfur is 22 g
But;
Moles = Mass ÷ Molar mass
Molar mass of Cadmium = 112.411 g/mol
Moles of Cadmium = 78 g ÷ 112.411 g/mol
= 0.694 moles
= 0.69 moles
Molar mass of sulfur is 32.065 g/mol
Moles of sulfur = 22 g ÷ 32.065 g/mol
= 0.686 moles
= 0.69 moles
<h3>Step 3: Determine the whole number mole ratio of Cadmium to sulfur</h3>
Cadmium : Sulfur
Cd : S
0.69 moles : 0.69 moles
0.69/0.69 : 0.69/0.69
1 : 1
Therefore, the empirical formula of greenockite is CdS
Oil and acid separate into there own layers and can not mix with out being forced by something
<h3>
Answer:</h3>
132.03 g
<h3>
Explanation:</h3>
<u>We are given;</u>
- The equation for the reaction as;
Fe₂O₃ + 3CO → 2Fe + 3CO₂
- Molar masses of CO and CO₂ as 28.01 g/mol and 44.01 g/mol respectively
- Mass of CO as 84 grams
We are required to calculate the mass of CO₂ that will produced.
<h3>Step 1: Calculate the number of moles of CO</h3>
Moles = Mass ÷ Molar mass
Molar mass of CO = 28.01 g/mol
Therefore;
Moles of CO = 84 g ÷ 28.01 g/mol
= 2.9989 moles
= 3.0 moles
<h3>Step 2: Calculate the number of moles of CO₂</h3>
- From the reaction, 3 moles of CO reacts to produce 3 moles of CO₂
- Therefore; the mole ratio of CO to CO₂ is 1 : 1
- Hence; Moles of CO = Moles of CO₂
Moles of CO₂ = 3.0 Moles
But; mass = Moles × molar mass
Thus, mass of CO₂ = 3.0 moles × 44.01 g/mol
= 132.03 g
Hence, the mass of CO₂ produced from the reaction is 132.03 g
Answer:
If an object is accelerating the forces acting on the object are BALANCED.
Explanation
if an object is moving at a constant rate of acceleration, the the forces acting upon it are balanced .