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SIZIF [17.4K]
3 years ago
10

The table shows the specific heat of four substances—brick, dry soil, paper, and water. If all four substances were exposed to s

unlight for the same amount of time, which substance would heat up the slowest?

Chemistry
2 answers:
Anvisha [2.4K]3 years ago
7 0
The specific heat<span> is the amount of </span>heat<span> per unit mass required to raise the temperature by one degree Celsius. Therefore, a high value of specific heat would mean that more heat is needed in order for the temperature to increase. The correct answer would be water since it has the highest specific heat of the choices given.</span>
disa [49]3 years ago
3 0

Water - It has the highest specific heat and therefore is the substance that would heat up the slowest.

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3 years ago
Hydroxylamine is a weak molecular base with kb = 6.6 x 10-9. what is the ph of a 0.0500 m solution of hydroxylamine?
7nadin3 [17]
Answer is: pH of hydroxylamine solution is 9,23.

Kb(NH₂OH) = 1,8·10⁻⁵<span>.
c</span>₀(NH₂OH)<span> = 0,0500 M = 0,05 mol/L.
c(NH</span>₂⁺) = c(OH⁻) = x.

c(NH₂OH<span>) = 0,05 mol/L - x.
Kb = c(NH</span>₂⁺) · c(OH⁻) / c(NH₂OH).

0,0000000066 = x² /  (0,05 mol/L - x). 

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4 0
3 years ago
How does doubling the volume of solvent affect the concentration of the solution?
Alex17521 [72]

Answer:

Molarity is halved when the volume of solvent is doubled.

Explanation:

Using the dilution equation (volume 1)(molarity 1)=(volume 2)(molarity 2), we can demonstrate the effects of doubling volume.

Suppose the starting volume is 1 L and the starting molarity is 1 M, and doubling the volume would make the final volume 2 L.

Plugging these numbers into the equation, we can figure out the final molarity.

(1 L)(1 M)=(2 L)(X M)

X M= (1 L x 1 M)/(2 L)

X M= 1/2 M

This shows that the molarity is halved when the volume of solvent is doubled.

8 0
3 years ago
As discussed in class, the Fischer esterification reactants and products are at equilibrium. How was the equilibrium of the reac
german

Answer:

See explanation

Explanation:

The particular reactants in the Fischer esterification reaction were not stated.

Generally, a Fischer esterification is a reaction that proceeds as follows;

RCOOH + R'OH ⇄RCOOR' + H2O

This reaction occurs in the presence of an acid catalyst.

We can shift the equilibrium of this reaction towards the products side in two ways;

I) use of a large excess of either of the reactants

ii) removal of one of the products as it is formed.

Any of these methods shifts the equilibrium of the Fischer esterification reaction towards the products side.

4 0
3 years ago
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