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Finger [1]
2 years ago
10

Name the process which takes place when

Chemistry
2 answers:
Lady_Fox [76]2 years ago
5 0

Explanation:

Chlorine gas bleaches the damp litmus (red or blue). Bleaching is an oxidation process.

Gnom [1K]2 years ago
4 0

Answer:

Bleaching is and oxidation

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If the pH of a 1.00-in. rainfall over 1800 miles2 is 3.70, how many kilograms of sulfuric acid, H2SO4, are present, assuming tha
NARA [144]
There are 2.32 x 10^6 kg sulfuric acid in the rainfall. 

Solution: 
We can find the volume of the solution by the product of 1.00 in and 1800 miles2: 
     1800 miles2 * 2.59e+6 sq m / 1 sq mi = 4.662 x 10^9 sq m 
     1.00 in * 1 m / 39.3701 in = 0.0254 m  
     Volume = 4.662 x 10^9 m^2 * 0.0254 m
                  = 1.184 x 10^8 m^3 * 1000 L / 1 m3
                  = 1.184 x 10^11 Liters 

We get the molarity of H2SO4 from the concentration of [H+] given by pH = 3.70: 
     [H+] = 10^-pH = 10^-3.7 = 0.000200 M 
     [H2SO4] = 0.000100 M  
 
By multiplying the molarity of sulfuric acid by the volume of the solution, we can get the number of moles of sulfuric acid: 
     1.184 x 10^11 L * 0.000100 mol/L H2SO4 = 2.36 x 10^7 moles H2SO4 

We can now calculate for the mass of sulfuric acid in the rainfall: 
     mass of H2SO4 = 2.36 x 10^7 moles * 98.079 g/mol
                               = 2.32 x 10^9 g * 1 kg / 1000 g
                               = 2.32 x 10^6 kg H2SO4
3 0
3 years ago
Read 2 more answers
Special structures in the cells of plants capture sunlight energy to power photosynthesis. What materials must plants obtain fro
Svetach [21]

Answer:

Sunlight

Water

And carbon dioxide

Additional information :

6CO2 + 6H2O → C6H12O6 + 6O2

3 0
2 years ago
Identify the limiting reactant when 1.22 g of O2 reacts with 1.05 g H2 to produce water.
kupik [55]
The reaction between oxygen, O2, and hydrogen, H2, to produce water can be expressed as,

                    2H2 + O2 --> 2H2O

The masses of each of the reactants are calculated below.

          2H2 = 4(1.01 g) = 4.04 g
          O2 = 2(16 g) = 32 g

Given 1.22 grams of oxygen, we determine the mass of hydrogen needed.
        (1.22 g O2)(4.04 g H2 / 32 g O2) = 0.154 g of O2

Since there are 1.05 grams of O2 then, the limiting reactant is 1.22 grams of oxygen.


<em>Answer: 1.22 g of oxygen</em>
4 0
3 years ago
Balancing Chemical Equation<br> Na+Br2=NaBr
solniwko [45]

Answer:

2Na + Br2 = 2NaBr

Explanation:

In order to balance a chemical equation you make the make sure both sides have the same number of atoms on each side, you do this by multiplying on both sides as if it was a algebraic equation.

Na+ Br2 = NaBr

Na × 2 = Na2

Na × 2 = Na2

Br × 2 = Br2

2Na + Br2 = 2NaBr

Hope this helps.

7 0
3 years ago
Which water cycle processes might be responsible for helping to clean/ filter the water? Explain.
Leya [2.2K]

to be as exact as i can it is all of them they all work together to make water good.


7 0
3 years ago
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