Strange question, as normally we would not calculate the "area of the tire." A tire has a cross-sectional area, true, but we don't know the outside radius of the tire when it's mounted on the wheel.
We could certainly calculate the area of a circle with radius 8 inches; it's
A = πr^2, or (here) A = π (8 in)^2 = 64π in^2.
The circumference of the wheel (of radius 8 in) is C = 2π*r, or 16π in.
The numerical difference between 64π and 16π is 48π; this makes no sense because we cannot compare area (in^2) to length (in).
If possible, discuss this situatio with your teacher.
The cosine of A is (adjacent side)/(hypotenuse) = 55/73. Do the division, then find the angle whose cosine is that number. The whole thing takes maybe 6 or 7 seconds with your calculator. It's choice-B.
I’m confused what do we have to do with the promblem do we Evaluate the function or..... if u evaluate the function the answe is 2x +10= x= 10=18x =
65 = l - 15d; continuous
65 is the loaf of bread, and -15d is when Diep cuts 15cm of the bread for his lunch.
The graph is continuous because it is following a decreasing pattern of -15 per day. If the information were put on a data graph the line formed would be straight.
L = length
W = width
P = perimeter
Equations:
L = 2W + 5
2L + 2W = P
P = 88
Solve using the equations above:
2(2W + 5) + 2W = 88
4W+ 10 + 2W = 88
6W + 10 = 88
6W = 78
w=16
the width is 16 centimeters
