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Alexus [3.1K]
3 years ago
5

The wavelength of the sound is 0.750m. What is the frequency?

Physics
1 answer:
kifflom [539]3 years ago
6 0

wavelength = speed/frequency


 ==> freq. = speed/wavelength = 342.5/0.75 = 456.67 Hz.

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Work is done on an object only if the force and displacement are __________?
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It’s either movement or work or that’s what a quizzie said
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3 years ago
Why did the scientific community initially reject Wegener's theory of continental drift?
zavuch27 [327]

Answer:

A. Wegener could not explain what made the continents move.

Explanation:

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What happens to potential energy when a skier goes down the hill? <br> A. Decrease <br> B. Increase
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Question: What happens to potential energy when a skier goes down the hill?

Answer: Decrease

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question answered by

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4 0
3 years ago
Two children are riding on a merry-go-round that is rotating with a constant angular speed. Abbie is one meter from the center o
klio [65]

Answer:

The acceleration of Abbie is half of the Zak's.

Explanation:

The centripetal acceleration of an object on a circular path is given by :

a=r\omega^2

Two children are riding on a merry-go-round that is rotating with a constant angular speed. Let r_1 is distance of Abbie from the merry-go-round and r_2 is distance of Zak's from the merry-go-round. Acceleration of Abbie is :

a_1=r_1\omega^2 ...... (1)

r_1=1\ m

Acceleration of Zak's is :

a_2=r_2\omega^2 .......(2)

r_2=2\ m

Dividing equation (1) and (2) we get :

\dfrac{a_1}{a_2}=\dfrac{r_1}{r_2}\\\\\dfrac{a_1}{a_2}=\dfrac{1}{2}\\\\a_1=\dfrac{a_2}{2}

So, the acceleration of Abbie is half of the Zak's.

7 0
3 years ago
A glider is gliding through the air at a height of 416 meters with a speed of 45.2 m/s. The glider dives to a height of 278 mete
Verdich [7]

Answer:

<em>The glider's new speed is 68.90 m/s</em>

Explanation:

<u>Principle Of Conservation Of Mechanical Energy</u>

The mechanical energy of a system is the sum of its kinetic and potential energy. When the only potential energy considered in the system is related to the height of an object, then it's called the gravitational potential energy. The kinetic energy of an object of mass m and speed v is

\displaystyle K=\frac{1}{2}mv^2

The gravitational potential energy when it's at a height h from the zero reference is

U=mgh

The total mechanical energy is

M=K+U

\displaystyle M=\frac{1}{2}mv^2+mgh

The principle of conservation of mechanical energy states the total energy is constant while no external force is applied to the system. One example of a non-conservative system happens when friction is considered since part of the energy is lost in its thermal manifestation.

The initial conditions of the problem state that our glider is glides at 416 meters with a speed of 45.2 m/s. The initial mechanical energy is

\displaystyle M_1=\frac{1}{2}m(45.2)v_o^2+m(9.8)(416)

Operating in terms of m

\displaystyle M_1=1021.52m+4076.8m

\displaystyle M_1=5098.32m

Then we know the glider dives to 278 meters and we need to know their final speed, let's call it v_f. The final mechanical energy is

\displaystyle M_2=\frac{1}{2}mv_f^2+m(9.8)(278)

Operating and factoring

\displaystyle M_2=m(\frac{1}{2}v_f^2+2724.4)

Both mechanical energies must be the same, so

\displaystyle m(\frac{1}{2}v_f^2+2724.4)=5098.32m

Simplifying by m and rearranging

\displaystyle \frac{v_f^2}{2}=5098.32-2724.4

Computing

v_f=\sqrt{4747.84}=68.90\ m/s

The glider's new speed is 68.90 m/s

8 0
3 years ago
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