Answer: 580 x 10^-3 J
Explanation:
0.6mm is 0.6/1000 = 600*10^-6 m
The plate area is .17*.17 = 28.9*10^-3 m^2
Air:
The voltage that can be sustained by 0.60 mm of air dielectric is:
V = 3.0*10^6* 600*10^-6 = 1800 V
The capacitance is:
C = ε*A/d = 8.854*10^-12 * 28.9*10^-3/600*10^-6 = 426*10^-12 F = 426 pF
The energy stored in a capacitor is:
E = (1/2)*C*V^2 = (1/2)*426*10^-12*(1800)^2 = 691*10^-6 J
Teflon:
The voltage is:
V = 60*10^6* 600*10^-6 = 36*10^3 = 36 kV
According to the listed reference, the relative dielectric constant for teflon is 2.1, this figure multiplies the "ε" of free space.
The capacitance is:
C = ε*A/d = 2.1*8.854*10^-12 * 28.9*10^-3/600*10^-6 = 896*10^-12 F = 896 pF
It would have been easier to note that the capacitance is 2.1 times the air-dielectric case.
The maximum energy stored is:
E = (1/2)*C*V^2 = (1/2)* 896*10^-12* (36*10^3)^2 = 580*10^-3 J
1. True
2. True
3. True
4. True
5. False
6. False
7. True
Answer:
15? I actually don't know
