Answer:
The angular acceleration of the wheel is 15.21 rad/s².
Explanation:
Given that,
Time = 5 sec
Final angular velocity = 96.0 rad/s
Angular displacement = 28.0 rev = 175.84 rad
Let
be the angular acceleration
We need to calculate the angular acceleration
Using equation of motion

Put the value in the equation

......(I)
Again using equation of motion

Put the value in the equation

On multiply by 5 in both sides
....(II)
On subtract equation (I) from equation (II)




Hence, The angular acceleration of the wheel is 15.21 rad/s².
Answer:
we could use the formula, v=u+at,
65=25+a (10), a=4 , since the motion is declerating we have a=-4 m/s2
The force needed to overcome sliding friction is more than the force needed to overcome rolling friction or static or even fluid
Answer:
The final position made with the vertical is 2.77 m.
Explanation:
Given;
initial velocity of the ball, V = 17 m/s
angle of projection, θ = 30⁰
time of motion, t = 1.3 s
The vertical component of the velocity is calculated as;

The final position made with the vertical (Yf) after 1.3 seconds is calculated as;

Therefore, the final position made with the vertical is 2.77 m.