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Lena [83]
3 years ago
15

What happens to potential energy when a skier goes down the hill? A. Decrease B. Increase

Physics
1 answer:
luda_lava [24]3 years ago
4 0

Question: What happens to potential energy when a skier goes down the hill?

Answer: Decrease

Explanation: As the skier begins the descent down the hill potential energy is lost and kinetic energy is going to start acting

question answered by

(jacemorris04)

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g A rotating wheel requires 5.00 s to rotate 28.0 revolutions. Its angular velocity at the end of the 5.00-s interval is 96.0 ra
Setler [38]

Answer:

The angular acceleration of the wheel is 15.21 rad/s².

Explanation:

Given that,

Time = 5 sec

Final angular velocity = 96.0 rad/s

Angular displacement = 28.0 rev = 175.84 rad

Let \alpha be the angular acceleration

We need to calculate the angular acceleration

Using equation of motion

\theta=\omega_{i} t+\dfrac{1}{2}\alpha t^2

Put the value in the equation

175.84=\omega_{i}\times 5+\dfrac{1}{2}\times\alpha\times(5)^2

175.84=\omega_{i}\times 5+12.5\alpha......(I)

Again using equation of motion

\omega_{f}=\omega_{i}+\alpha t

Put the value in the equation

96.0=\omega_{i}+\alpha \times 5

On multiply by 5 in both sides

480=\omega_{i}\times 5+\alpha\times 25....(II)

On subtract equation (I) from equation (II)

480-175.84=\alpha(25-5)

304.16=\alpha\times20

\alpha=\dfrac{304.16}{20}

\alpha=15.21\ rad/s^2

Hence, The angular acceleration of the wheel is 15.21 rad/s².

5 0
3 years ago
An object is moving east, and its velocity changes from 65 m/s to 25 m/s in 10 seconds. Which describes the acceleration? negati
hammer [34]

Answer:

we could use the formula, v=u+at,

65=25+a (10), a=4 , since the motion is declerating we have a=-4 m/s2

5 0
3 years ago
What is the compare the strength of static,sliding,and rolling friction
Inga [223]
The force needed to overcome sliding friction is more than the force needed to overcome rolling friction or static or even fluid 
7 0
4 years ago
1. What are the units of : pressure, force , area
White raven [17]

Pressure- Pascal(N/m^2)

Force- Newton

Area-m^2(Square metre)

<u>Explanation:</u>

  • Pressure is force continuous force applied to an object. The applied force is always perpendicular to the surface of the object.
  • Force is a push or pulls on an object by an external body where it changes its state from rest to motion.
  • Force is said to have both magnitude and direction.
  • Area is the portion that shows the scale of a 2D form or configuration in the level. The covering area is its analog on the 2D surface of a 3D object.
6 0
3 years ago
If a player through a basketball to the target with an initial velocity of 17 m/s making an angle of 30 degrees with the horizon
Svetllana [295]

Answer:

The final position made with the vertical is 2.77 m.

Explanation:

Given;

initial velocity of the ball, V = 17 m/s

angle of projection, θ = 30⁰

time of motion, t = 1.3 s

The vertical component of the velocity is calculated as;

V_y = Vsin \theta\\\\V_y = 17 \times sin(30)\\\\V_y = 8.5 \ m/s

The final position made with the vertical (Yf) after 1.3 seconds is calculated as;

Y_f = V_yt  - \frac{1}{2}g t^2\\\\Y_f = (8.5 \times 1.3 ) - (\frac{1}{2} \times 9.8 \times 1.3^2)\\\\Y_f = 11.05 \ - \ 8.281\\\\Y_f = 2.77 \ m

Therefore, the final position made with the vertical is 2.77 m.

3 0
3 years ago
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