What are the x intercept and y intercept of the graph of 12x-4y=48

6700 dollars is placed in an account with an annual interest rate of 8%. How much will be in the account after 24 years, to the

daser333 [38]

$\bf \qquad \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$6700\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
t=years\to &24
\end{cases}
\\\\\\
A=6700(1+0.08\cdot 24)\implies A=19,564.00$

5 0

3 years ago

Read 2 more answers

The $414 price charges a store for a small refrigerator consists of the refrigerator's original cost to the store plus a profit

navik [9.2K]

Answer:

Step-by-step explanation:

the question is not formatted well

<em>A store charges $414 for a small refrigerator, the price consists of the refrigerator's original cost to the store plus a profit 15% what was the refrigerator's original cost to the store?</em>

Step one:

given data

we are told that the price of the small refrigerator contains both the original price and 15% profit

mathematically

$414= original price + 15% profit

Step two:

let us solve for 15% of 414

=(15/100)*414

=0.15*414

=$62.1

This shows that the profit is $62.1

let the original price be x

$414= x + 62.1

solve for x

x=414-62.1

x=351.9

<u>The refrigerator's original cost to the store $351.9</u>

4 0

2 years ago

At the local farmers market, it costs $10 to rent a stand and $7 for every hour you stay. If you pay a total of $38, how many ho

zhenek [66]

4 hours

Step by step:
$38 - 10 = 28
28/7 = 4

7 0

2 years ago

Read 2 more answers

More math help pls. :)

Step2247 [10]

By using trigonometric relations, we will see that x = 9.97°.

<h3>How to find the missing angle?</h3>

First, we need to find the bottom cathetus of the smaller triangle, we will use the relation:

Tan(θ) = (opposite cathetus)/(adjacent cathetus).

Where:

θ = 26°
Adjacent cathetus = k
Opposite cathetus = 55ft.

Replacing that we get:

Tan(26°) = 50ft/k

Solving this for k, we get:

k = 55ft/tan(26°) = 112.8 ft

Now, we can see that the longer triangle adds 200ft to this cathetus, so now we will have:

angle = x
opposite cathetus = 55ft
adjacent cathetus = 112.8ft + 200ft = 312.8ft.

Then we have:

Tan(x) = (55ft/312.8ft)

Using the inverse tangent function in both sides, we get:

x = Atan(55ft/312.8ft) = 9.97°

If you want to learn more about right triangles, you can read:

brainly.com/question/2217700

6 0

2 years ago

A recent study focused on the number of times men and women who live alone buy take-out dinner in a month. Assume that the distr

Marianna [84]

Answer:

(a) Decision rule for 0.01 significance level is that we will reject our null hypothesis if the test statistics does not lie between t = -2.651 and t = 2.651.

(b) The value of t test statistics is 1.890.

(c) We conclude that there is no difference in the mean number of times men and women order take-out dinners in a month.

(d) P-value of the test statistics is 0.0662.

Step-by-step explanation:

We are given that a recent study focused on the number of times men and women who live alone buy take-out dinner in a month.

Also, following information is given below;

Statistic : Men Women

The sample mean : 24.51 22.69

Sample standard deviation : 4.48 3.86

Sample size : 35 40

<em>Let </em> $\mu_1$ <em> = mean number of times men order take-out dinners in a month.</em>

<em /> $\mu_2$ <em> = mean number of times women order take-out dinners in a month</em>

(a) So, Null Hypothesis, $H_0$ : $\mu_1-\mu_2$ = 0 {means that there is no difference in the mean number of times men and women order take-out dinners in a month}

Alternate Hypothesis, $H_A$ : $\mu_1-\mu_2\neq$ 0 {means that there is difference in the mean number of times men and women order take-out dinners in a month}

The test statistics that would be used here <u>Two-sample t test statistics</u> as we don't know about the population standard deviation;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t__n_1_-_n_2_-_2$

where, $\bar X_1$ = sample mean for men = 24.51

$\bar X_2$ = sample mean for women = 22.69

$s_1$ = sample standard deviation for men = 4.48

$s_2$ = sample standard deviation for women = 3.86

$n_1$ = sample of men = 35

$n_2$ = sample of women = 40

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(35-1)\times 4.48^{2}+(40-1)\times 3.86^{2} }{35+40-2} }$ = 4.16

So, <u>test statistics</u> = $\frac{(24.51-22.69)-(0)}{4.16 \sqrt{\frac{1}{35}+\frac{1}{40} } }$ ~ $t_7_3$

= 1.890

(b) The value of t test statistics is 1.890.

(c) Now, at 0.01 significance level the t table gives critical values of -2.651 and 2.651 at 73 degree of freedom for two-tailed test.

Since our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that there is no difference in the mean number of times men and women order take-out dinners in a month.

(d) Now, the P-value of the test statistics is given by;

P-value = P( $t_7_3$ > 1.89) = 0.0331

So, P-value for two tailed test is = 2 $\times$ 0.0331 = <u>0.0662</u>

4 0

3 years ago