C. Viral Hemorrhagic Fever is a form of marburg virus
Answer:
Rough endoplasmic reticulum and Mitochondria.
Explanation:
Disulfide bonds are known as covalent bonds. They are formed by the oxidation of 2 cysteines and these bonds can provide stability to proteins. These bonds mainly formed in intermembrane space of mitochondria and cellular compartments outside the cytoplasm endoplasmic reticulum. Both of these organelles present in an oxidation state providing an atmosphere for disulfide bond formation.
Cytoplasm and Nuclei mostly exit in reducing state because of the existence of disulfide reductase which is reducing the disulfide bonds between the cysteine residue to thiolate state. So, the disulfide bond formation will not happen.
An immunoglobulin molecule of any class with regions symbolized as C or V, H or L, has a light chain made up of one C region and one V region.
The glycoproteins known as immunoglobulins (Ig), often known as antibodies, are created by plasma cells. A number of immunogens, including bacterial proteins, promote B cells' conversion to plasma cells. These cells, which make proteins, are involved in humoral immune reactions to bacteria, viruses, fungi, parasites, cellular antigens, chemicals, and synthetic compounds. Using a B-cell receptor, the immunogen or antigen adheres to the B cells' cell surface (BCR).
As a result, a signal is generated that directs the activation of transcription factors, leading to the manufacture of highly specific antibodies for the immunogen that initially activated the B cell. Furthermore, one B cell clone produces immunoglobulin (specificity). Two light chains and two heavy chains that alternate in a light-heavy-heavy-light pattern make up antibodies, also known as immunoglobulins. Therefore, choice A is the right response.
Learn more about immunoglobulins here, brainly.com/question/28203010
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Answer:
D. the genetic material of living organisms
Explanation:
