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GaryK [48]
3 years ago
5

Consider a sign suspended on a boom that is supported by a cable, as shown. What is the proper equation to use for finding the n

et force in the y direction?
Fnety = (FT)(sin 32°) + Fg
Fnety = (FT)(sin 32°) – Fg
Fnety = (FT)(cos 32°) + Fg
Fnety = (FT)(cos 32°) – Fg
Physics
2 answers:
-Dominant- [34]3 years ago
8 0

Answer:

B: Fnety = (FT)(sin 32°) – Fg

Explanation:

oksian1 [2.3K]3 years ago
3 0
Fnety = (FT)(sin 32°) – Fg Or the answer B, I checked it.
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A gas undergoes two processes. In the first, the volume remains constant at 0.200 m3 and the pressure increases from 1.00×105 Pa
Alborosie
<h2>The work done = - 2 x 10⁴ J</h2>

Explanation:

In the first case , the volume is kept constant and pressure varies .

In isothermal process  , the work done

W₁ = V x ΔP

here V is the volume of gas and ΔP is the change in pressure

Thus W₁ = 0

Because there is no change in volume , therefore displacement is zero .

In second case pressure is constant , but volume changes

Thus W₂ = P x ΔV

here P is the pressure  and ΔV is the change in volume

Therefore W₂ = 4 x 10⁵ x 5 x 10⁻² = 2 x 10⁴ J

The total work done W = - 2 x 10⁴ J

Because the work done in compression is negative .

7 0
4 years ago
A 4500 kg car accelerates from rest to 45.0
Llana [10]

The car undergoes an acceleration <em>a</em> such that

(45.0 km/h)² - 0² = 2 <em>a</em> (90 m)

90 m = 0.09 km, so

(45.0 km/h)² - 0² = 2 <em>a</em> (0.09 km)

Solve for <em>a</em> :

<em>a</em> = (45.0 km/h)² / (2 (0.09 km)) = 11,250 km/h²

Ignoring friction, the net force acting on the car points in the direction of its movement (it's also pulled down by gravity, but the ground pushes back up). Newton's second law then says that the net force <em>F</em> is equal to the mass <em>m</em> times the acceleration <em>a</em>, so that

<em>F</em> = (4500 kg) (11,250 km/h²)

Recall that Newtons (N) are measured as

1 N = 1 kg • m/s²

so we should convert everything accordingly:

11,250 km/h² = (11,250 km/h²) (1000 m/km) (1/3600 h/s)² ≈ 0.868 m/s²

Then the force is

<em>F</em> = (4500 kg) (0.868 m/s²) = 3906.25 N ≈ 3900 N

8 0
4 years ago
As wavelength decreases, frequency and energy _________________;
earnstyle [38]

Answer:

Increase

Explanation:

The best way for me to visualize the relation between wavelength, frequency, and energy is to think about actual ocean waves. Wavelength is a measure of the distance between two equivalent points on consecutive waves (think wave peak to wave peak). Lets say you are building a sand castle and want to see how many waves hit your castle over a period of 10 seconds. If the distance between each wave is 10 ft and the wave is traveling at 1 foot per second then you will only have one wave hit your castle. If the wavelength is 1/2 that (5 ft) then you will have 2 waves hit your castle in the same amount of time. This is the same concept behind waves in physics. The smaller the distance between each wave, the more waves and therefore more energy that will be delivered.

4 0
3 years ago
A jet accelerates at a=3.92 m/s2 from rest until it reaches its takeoff velocity of 360 km/hr. It has to travel for 5 seconds at
Art [367]

Answer:

\Delta s = 1775.510\,m

Explanation:

The minimum distance for takeoff is:

\Delta s = \Delta s_{1} + \Delta s_{2}

\Delta s = \frac{v_{f}^{2}-v_{o}^{2}}{2\cdot a} + v_{f}\cdot \Delta t

\Delta s = \frac{(100\,\frac{m}{s} )^{2}-(0\,\frac{m}{s} )^{2}}{2\cdot (3.92\,\frac{m}{s^{2}})}+(100\,\frac{m}{s} )\cdot (5\,s)

\Delta s = 1775.510\,m

7 0
3 years ago
You throw an 18.0 N rock into the air from ground level and observe that, when it is 15.0 m high, it is traveling upward at 17.0
stellarik [79]

Answer:

Vi = 24.14 m/s

Explanation:

If we apply Law of Conservation of Energy or Work-Energy Principle here, we get: (neglecting friction)

Loss in K.E of the Rock = Gain in P.E of the Rock

(1/2)(m)(Vi² - Vf²) = mgh

Vi² - Vf² = 2gh

Vi² = Vf² + 2gh

Vi = √(Vf² + 2gh)

where,

Vi = Rock's Speed as it left the ground = ?

Vf = Final Speed = 17 m/s

g = 9.8 m/s²

h = height of rock = 15 m

Therefore,

Vi = √[(17 m/s)² + 2(9.8 m/s²)(15 m)]

Vi = √583 m²/s²

<u>Vi = 24.14 m/s</u>

4 0
4 years ago
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