For a point charge, how does the potential vary with distance from the point charge, r?
a constant
b. r.
c. 1/r.
d.
.
e.
.
Answer:
The correct option is C
Explanation:
Generally for a point charge the electric potential is mathematically represented as

Here we can deduce that the electric potential varies inversely with the distance i.e

So
Answer:
A.
Explanation:
If its at a height the Gratitude of it falling down with only Gravity if Any other Forces are acting on it so as Friction But Sideways.
That's false. It's the other way around. One light year is a distance that's a little farther than 63,000 astronomical units.
Explanation:
Given that,
Input force on a simple machine, F = 2 N
The output force on a simple machines, F' = 4 N
The ratio of the output force to the input force of any simple machines is called its mechanical advantage. Mathematically, it is given by :

Putting the value of F and F' in above equation. We get :

m = 2
So, the mechanical advantage of the simple machines is 2. Hence, this is the required solution.
Answer:
f = 1.354*10^{20} Hz
Explanation:
By conservation of linear momentum, wavelength shift due to collision of photon to electron is given by following formula

where h is plank constant = 6.626*10^{-34}
c = speed of light = 3*10^{8} m/s
scattered angle = 60 degree
m = rest mass of electron = 9*10^{-31}


we know that 1 pm = 10^{-12}m


f = 1.354*10^{20} Hz