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3 years ago

As wavelength decreases, frequency and energy _________________;

Physics

1 answer:

earnstyle [38]3 years ago

4 0

Answer:

Increase

Explanation:

The best way for me to visualize the relation between wavelength, frequency, and energy is to think about actual ocean waves. Wavelength is a measure of the distance between two equivalent points on consecutive waves (think wave peak to wave peak). Lets say you are building a sand castle and want to see how many waves hit your castle over a period of 10 seconds. If the distance between each wave is 10 ft and the wave is traveling at 1 foot per second then you will only have one wave hit your castle. If the wavelength is 1/2 that (5 ft) then you will have 2 waves hit your castle in the same amount of time. This is the same concept behind waves in physics. The smaller the distance between each wave, the more waves and therefore more energy that will be delivered.

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in which item is energy stored in the form of gravitational potential energy A)a slice of bread B)a compressed string C)an apple

olchik [2.2K]

For this case, in the next item we have gravitational potential energy:

An apple in a tree.

Suppose we define our reference system at the floor level.

Suppose the apple is at a height h from the floor and has mass m.

The gravitational potential energy of the apple is given by:

U = mgh

Where,

m: apple mass

h: height of the apple with respect to the floor

g: acceleration due to gravity

Answer:

C) an apple on a tree

7 0

4 years ago

Read 2 more answers

A mass m1=1.5 kg rests on a 30 degree ramp with a coefficient of kinetic friction = 0.40. Mass m1 is tied to another mass m with

soldier1979 [14.2K]

Answer:

m = 2.31 Kg

Explanation:

given,

m₁ is the mass rest on the inclined plane = 1.5 Kg

inclination of plane = 30°

Kinetic friction = μ = 0.4

acceleration of the body = 2.68 m/s²

mass m is hanging = ?

using equation to solve

T - m₁g sin θ - μ m₁g cos θ = m₁ a

on the block on inclined plane there will be acting tension T on the string,

mg sin θ will be the force acting opposite to the tension on the string and a frictional force will be acting which will oppose moment which will be equal to μ m₁g cos θ

T = m₁(g sin θ + μ g cos θ + a )

T = 1.5 (9.8 x sin 30° + 0.4 x 9.8 x cos 30°+ 2.68 )

T = 16.46 N

now, forces on the other side of pulley

m g - T = m a

m (g - a ) = T

$m = \dfrac{16.46}{9.8-2.68}$

m = 2.31 Kg

6 0

3 years ago

A cheetah spotted a Gazelle. The cheetah runs at its top speed of 30 m/s for 15 seconds. Durning this time , a gazelle ,160 m fr

Xelga [282]

Answer:

A) 450 m

B) 27 m/s

C) 81 m, 243 m

D) Gazelle

Explanation:

Since, the Cheetah is running at constant speed. Therefore, we use the equation:

s₁ = v₁t

where,

s₁ = distance covered by Cheetah = ?

v₁ = speed of Cheetah = 30 m/s

t = time taken = 15 s

Therefore,

s₁ = (30 m/s)(15 s)

s₁ = 450 m

For final speed of Gazelle at the end of 6 s acceleration time we use 1st equation of motion:

Vf = Vi + at

where,

Vf = Final Speed of Gazelle at the end of 6 s = ?

Vi = Initial Speed of Gazelle = 0 m/s (Since, Gazelle is initially at rest)

t = time taken = 6 s

a = acceleration = 4.5 m/s²

Therefore,

Vf = (0 m/s) + (4.5 m/s²)(6 s)

Vf = 27 m/s

For the distance covered by Gazelle at the end of 6 s acceleration time we use 2nd equation of motion:

s₂ = Vi t + (0.5)at²

where,

Vi = Initial Speed of Gazelle = 0 m/s (Since, Gazelle is initially at rest)

t = time taken = 6 s

a = acceleration = 4.5 m/s²

Therefore,

s₂ = (0 m/s)(6 s) + (0.5)(4.5 m/s²)(6 s)²

s₂ = 81 m

Now, for the distance covered during the last 9 s at constant velocity Vf, we use equation:

s₃ = Vf t

where,

s₃ = distance covered by Gazelle in last 9 s = ?

t = time = 9 s

Therefore:

s₃ = (27 m/s)(9 s)

s₃ = 243 m

We know that, at the end of 15 seconds:

Distance covered by Cheetah = s₁ = 450 m

Distance Covered by Gazelle = s₂ + s₃ = 81 m + 243 m = 324 m

If we take the initial position of Cheetah as origin. Then the positions of both Gazelle and Cheetah with respect to origin will be:

Position of Cheetah = 450 m ahead of origin

Position of Gazelle = 324 m + 160 m = 484 m (Since, Gazelle was initially 160 m ahead of Cheetah)

Hence, it is clear that Gazelle is ahead at the end of 15 s.

5 0

3 years ago

Magnetic fields go from the north poles of magnets to the south poles of magnets. true or false

Novay_Z [31]

The Answer is true, the saying opposites attract are true for magnets when poles match though they repel.

7 0

3 years ago

The energy an object possesses due to its form and position is know as

zvonat [6]

I believe the energy being described is the potential energy. Potential energy is the stored energy, it is the energy an object has because of its position or shape. It is also the energy possessed by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors. The major types of energy include the gravitational energy of an object that depends on its mass and its distance from the center of mass.

5 0

4 years ago