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TEA [102]
3 years ago
5

The weather behind a cold front is dominated by which of the following?

Chemistry
1 answer:
Pachacha [2.7K]3 years ago
6 0
The weather behind the cold front is considered a High
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Why is carbon dioxide called a gas and not vapour?
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Explanation:

CO2 is called as gas because it exist in single thermodynamics state i.e CO exist in gases state only at room temperature.

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Which energy transition may take place in the atom if its electron has absorbed a photon?
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When the electron absorbs a photon it goes from a lower energy state to a higher one.
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In which of the following examples has a chemical reaction occurred?
katrin2010 [14]
"A" is the answer. The chemical reaction is when the batter becomes brown.

B is mixing C is mass becoming a liquid and D. is dissolving no chemical reaction happened there.

Hope that helps!
3 0
3 years ago
How many moles of oxygen gas react to yield 0.200 mole water? . . C5H12(g) + 8 O2(g) = 5 CO2(g) + 6H2O(g)
Harlamova29_29 [7]
C5H12(g) + 8 O2(g) = 5 CO2(g) + 6H2O(g) 
molar ratio of H2O to O = 6:8 
<span>we have 0.200 moles of H2O so we need 0.200 * 8/6 moles of O2 = 0.267 moles of O2 

Therefore, there will be 0.267 moles of O2 gas required to yield 0.2 moles of H20.


I hope my answer has come to your help. Thank you for posting your question here in Brainly.
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4 0
3 years ago
Complete combustion of 8.60 g of a hydrocarbon produced 26.5 g of CO2 and 12.2 g of H2O. What is the empirical formula for the h
amid [387]

The empirical formula of the hydrocarbon is C_2H_3 if combustion of 8.60 g of a hydrocarbon produced 26.5 g of CO_2 and 12.2 g of H_2O.

<h3>What is an empirical formula?</h3>

A chemical formula showing the simplest ratio of elements in a compound rather than the total number of atoms in the molecule CH_2O is the empirical formula for glucose.

1 mole of carbon dioxide contains a mass of 44 g, out of which 12 g are carbon.

Hence, in this case the mass of carbon in 8.46 g of CO_2:

(\frac{12}{44}) × 8.46 = 2.3073 g

1 mole of water contains 18 g, out of which 2 g is hydrogen;

Therefore, 2.6 g of water contains;

(\frac{2}{18} × 2.6 = 0.2889 g of hydrogen.

Therefore, with the amount of carbon and hydrogen from the hydrocarbon, we can calculate the empirical formula.

We first calculate the number of moles of each,

Carbon = \frac{2.3073}{12}  = 0.1923 moles

Hydrogen = \frac{0.2889}{1}= 0.2889 moles

Then, we calculate the ratio of Carbon to hydrogen by dividing by the smallest number value;

            Carbon : Hydrogen

               \frac{0.1923}{0.1923} : \frac{0.2889}{0.1923}

                      1 :  1.5

                     (1 : 1.5) 2

                    = 2 : 3

Hence, the empirical formula of the hydrocarbon is C_2H_3.

Learn  more about the empirical formula here:

brainly.com/question/14044066

#SPJ1

8 0
2 years ago
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