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vazorg [7]
3 years ago
8

A geologist tests a rock containing calcium oxide by reacting it with hydrochloric acid. Water and calcium chloride form. What b

onds break?
Chemistry
2 answers:
faust18 [17]3 years ago
4 0
The bond that are broken from the reaction would be ionic bonds. Calcium oxide and hydrochloric acid are held by ionic bonds so that these are also the bonds being broken and are being formed as well. Hope this answers the question.
Zina [86]3 years ago
3 0

Answer:

Ca–O bonds in calcium oxide and H–O bonds in water

 

H–O bonds in water and Ca–Cl bonds in calcium chloride

 

Ca–Cl bonds in calcium chloride and H–Cl bonds in hydrochloric acid

 

Ca–O bonds in calcium oxide and H–Cl bonds in hydrochloric acid

??????

Explanation:

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The reaction 2NO(g)+Cl2(g)→2NOCl(g) is carried out in a closed vessel. If the partial pressure of NO is decreasing at the rate o
Luba_88 [7]

Answer : The rate of change of the total pressure of the vessel is, 10.5 torr/min.

Explanation : Given,

\frac{d[NO]}{dt} =21 torr/min

The balanced chemical reaction is,

2NO(g)+Cl_2(g)\rightarrow 2NOCl(g)

The rate of disappearance of NO = -\frac{1}{2}\frac{d[NO]}{dt}

The rate of disappearance of Cl_2 = -\frac{d[Cl_2]}{dt}

The rate of formation of NOCl = \frac{1}{2}\frac{d[NOCl]}{dt}

As we know that,

\frac{d[NO]}{dt} =21 torr/min

So,

-\frac{d[Cl_2]}{dt}=-\frac{1}{2}\frac{d[NO]}{dt}

\frac{d[Cl_2]}{dt}=\frac{1}{2}\times 21torr/min=10.5torr/min

And,

\frac{1}{2}\frac{d[NOCl]}{dt}=\frac{1}{2}\frac{d[NO]}

\frac{d[NOCl]}{dt}=\frac{d[NO]}=21torr/min

Now we have to calculate the rate change.

Rate change = Reactant rate - Product rate

Rate change = (21 + 10.5) - 21 = 10.5 torr/min

Therefore, the rate of change of the total pressure of the vessel is, 10.5 torr/min.

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