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meriva
2 years ago
15

A form of energy that is stored in a stretched rubber band is called

Chemistry
1 answer:
storchak [24]2 years ago
6 0
You input potential (stored<span>) </span>energy<span> into the </span>rubber band<span> system when you </span>stretched<span> the</span>rubber band<span> back. Because it is an </span>elastic<span> system, this kind of potential </span>energy<span> is specifically </span>called elastic<span> potential </span>energy<span>. ... When the </span>rubber band<span> is released, the potential </span>energy<span> is quickly converted to kinetic (motion) </span>energy<span>.</span>
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Help with this worksheet please (24pts)
Igoryamba
  • Atoms that loss or gain electrons are called ions. There are two types of ions: cations and anions.
  • Here, 2+ represents that Calcium (Ca) should gain 2 more electrons so that its number equals to that of protons.
  • 3- represents that Nitrogen (N) should loss 3 electrons to equivalent with the number of protons.
  • Here, anions are S^2-, P^3-, Se^2-, Br^-.
  • While cations are Cr^3+, Ag^+, Li^+, Ba^2+.
  • The number of protons of Magnesium (Mg) = 12
  • The number of nuetrons of Mg = 12
  • The number of electrons of Mg = 12

Hope you could get an idea from here.

Doubt clarification - use comment section.

7 0
2 years ago
_____ chemical reactions need a certain amount of activation energy to get started.
Anettt [7]

Answer:all

Explanation:

Because a reaction does not starts by itself unless some force is applied

3 0
3 years ago
Please answers the question​
frozen [14]
That is correct hope that helps
8 0
3 years ago
Calculate the standard enthalpy change for the reaction at 25 ∘ C. Standard enthalpy of formation values can be found in this li
meriva

Answer:

The standard enthalpy change for the reaction at 25^{0}\textrm{C} is -2043.999kJ

Explanation:

Standard enthalpy change (\Delta H_{rxn}^{0}) for the given reaction is expressed as:

\Delta H_{rxn}^{0}=[3mol\times \Delta H_{f}^{0}(CO_{2})_{g}]+[4mol\times \Delta H_{f}^{0}(H_{2}O)_{g}]-[1mol\times \Delta H_{f}^{0}(C_{3}H_{8})_{g}]-[5mol\times \Delta H_{f}^{0}(O_{2})_{g}]

Where \Delta H_{f}^{0} refers standard enthalpy of formation

Plug in all the given values from literature in the above equation:

\Delta H_{rxn}^{0}=[3mol\times (-393.509kJ/mol)]+[4mol\times (-241.818kJ/mol)]-[1mol\times (-103.8kJ/mol)]-[5mol\times (0kJ/mol)]=-2043.999kJ

4 0
2 years ago
What are the steps of natural selection?
blagie [28]

Answer:

The five steps involved in the process of natural selection are

Variation • Inheritance • Selection • Time • Adaptation

☆anvipatel77☆

•Expert•

Brainly Community Contributor

5 0
2 years ago
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