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Svetllana [295]
3 years ago
7

What words do scientist use to classify their ideas?​

Chemistry
1 answer:
Nady [450]3 years ago
6 0

Answer:

taxonomy

Explanation:

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BRAINLIST!!
Iteru [2.4K]

Answer:

B

as the flows along the outside edge of a curve it removes rock and soil from the river bank

6 0
2 years ago
2. Calculate the mass of 3.47x1023 gold atoms.
lapo4ka [179]

3.47 x 10^{23} atoms of gold have mass of 113.44 grams.

Explanation:

Data given:

number of atoms of gold = 3.47 x 10^{23}

mass of the gold in given number of atoms = ?

atomic mass of gold =196.96 grams/mole

Avagadro's number = 6.022 X 10^{23}

from the relation,

1 mole of element contains 6.022 x 10^{23} atoms.

so no of moles of gold given = \frac{3.47 X 10^{23}  }{6.022 X 10^{23} }

0.57 moles of gold.

from the relation:

number of moles = \frac{mass}{atomic mass of 1 mole}

rearranging the equation,

mass = number of moles x atomic mass

mass = 0.57 x 196.96

mass = 113.44 grams

thus, 3.47 x 10^{23} atoms of gold have mass of 113.44 grams

3 0
3 years ago
The element Europium exists in nature as two isotopes: 151Eu, which has a mass of 150.9196amu, and 153Eu, which has a mass of 15
Juliette [100K]

Answer:151 Eu= 48.01%

152 Eu= 51.99%

Explanation:

4 0
3 years ago
Zinc oxide adopts a face-centered cubic arrangement. Both Zinc ions and oxide ions adopt the face-centered cubic arrangement; wi
vichka [17]

Answer:

5.41 ×10⁻²²

Explanation:

We were told right from the question that both the Zinc ions and the Zinc oxide adopts a face-centered cubic arrangement.

Then, the number of ZnO molecule in one unit cell = 4

The standard molar mass of ZnO = 81.38g

Avogadro's constant = 6.023 × 10²³ mole

∴

The mass of one unit cell of zinc oxide can be calculated as:

= \frac{4*81.38}{6.023*10^{23}}

= 5.40461564×10⁻²²

≅ 5.41 ×10⁻²²

∴ The mass of one unit cell of zinc oxide = 5.41 ×10⁻²²

3 0
2 years ago
Rubidium is in Group I of the Periodic Table and bromine is in Group VII.
tensa zangetsu [6.8K]
The answer to this question would be C
7 0
3 years ago
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