Commonly the sea walls are used for preventing damage from tsunami. A special type of device is also used for detecting the tsunami called floating device.
<h3>
What are the technologies that could help reduce the damage from a tsunami?</h3>
Commonly seawalls are used for preventing damage from tsunamis. There is a network which is used for detecting the earthquake and tsunami and that network is known as Seismological network. This network helps the people to know about the earthquakes and tsunamis and reduces the damages of earthquakes and tsunamis.
The engineers also design a special type of special buoys which is also known as floating devices, these devices are placed near the coastal areas from where the tsunamis can be detected easily.
So we can conclude that commonly the sea walls are used for preventing damage from tsunami. A special type of device is also used for detecting the tsunami called floating device.
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Answer:
1.2 × 10⁸ m
Explanation:
You want to convert metres to nanometres.
Recall that the multiplying prefix nano- means × 10⁻⁹, so
1 nm = 1 × 10⁻⁹ m
The conversion factor is either
or
.
You choose the one that has the desired units (nm) on top. Then

Answer: They are the same.
Expatiation:
Buoyant force: An upward thrust exerted by any fluid on an object placed in it.
According to Archimedes' principle which states that 'upward thrust exerted by the fluid on an object immersed in a fluid whether partially or fully is equal to the weight of the fluid displaced by the immersed body'.This force acts in the upward direction at the center of mass of the displaced fluid.
Hence, it is correct to say that weight of the water displaced compare to the buoyant force are the same.
Answer: 2.75%
Explanation:
![pH=-log [H+]](https://tex.z-dn.net/?f=pH%3D-log%20%5BH%2B%5D)
![3.26 = -log [H+]](https://tex.z-dn.net/?f=3.26%20%3D%20-log%20%5BH%2B%5D)
![[H+] = 5.495\times 10^{-4} M](https://tex.z-dn.net/?f=%5BH%2B%5D%20%3D%205.495%5Ctimes%2010%5E%7B-4%7D%20M)

initial 0.020 0 0
eqm 0.020 -x x x
![K_a=\frac{[H+][A-]}{[HA]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH%2B%5D%5BA-%5D%7D%7B%5BHA%5D%7D)
![K_a=\frac{[x][x]}{[0.020-x]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5Bx%5D%5Bx%5D%7D%7B%5B0.020-x%5D%7D)

![K_a=\frac{[5.495\times 10^{-4}]^2}{[0.020-5.495\times 10^{-4}]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5B5.495%5Ctimes%2010%5E%7B-4%7D%5D%5E2%7D%7B%5B0.020-5.495%5Ctimes%2010%5E%7B-4%7D%5D%7D)

percent dissociation = ![\frac{[H^+_eqm]}{[Acid_{initial}]}\times 100](https://tex.z-dn.net/?f=%5Cfrac%7B%5BH%5E%2B_eqm%5D%7D%7B%5BAcid_%7Binitial%7D%5D%7D%5Ctimes%20100)
percent dissociation=
Thus percent dissociation= 2.75 %