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Ivan
4 years ago
6

What is the electron configuration for silicon

Chemistry
1 answer:
Serjik [45]4 years ago
7 0
<span>Ne 3s2 3p2. Thats the answer and i hope it helped!</span>
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Plz Help me with this ?
Arte-miy333 [17]

Answer:

Hey there!

This is a convergent boundary. Here, a oceanic crust collides with a continental crust.

Hope this helps :)

5 0
3 years ago
Read 2 more answers
How much heat is released when 27.6 g P C l subscript 3 cools from 83.1 °C to 55.6 °C? (The specific heat of P C l subscript 3 i
Paul [167]

Answer: Thus 663 J of heat  is released when 27.6 g PCl_3 cools from 83.1 °C to 55.6 °C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat released = ?

m = mass of substance = 27.6 g

C = specific heat capacity = 0.874J/g^0C

Initial temperature= T_i = 83.1^0C

Final temperature  = T_f  = 55.6^0c

Change in temperature ,\Delta T=T_f-T_i=(55.6-83.1)^0C=-27.5^0C

Putting in the values, we get:

Q=27.6g\times 0.874J/g^0C\times -27.5^0C=-663J

As the value of q is negative, it means the heat has been released and it is 663J

7 0
3 years ago
How many grams of a solution that is 5.2% sucrose by mass are needed to obtain 18g of sucrose
kirill115 [55]

Answer:

346.g of solution

Explanation:

In this case, if we have 5.2 % by mass it means that in <u>100 g of the solution we will have 5.2 g of glucose</u>. Therefore we can do the calculation:

<u>5.2 g of glucose = 100 g of solution</u>

18~g~of~glucose\frac{100~g~of~solution}{5.2~g~of~glucose}=346.15~g~of~solution

So, if we need 8 g of glucose we had to have 346.15 g of solution

This logic can work for all types of solutions. By mass (as in this case), by volume or mass/volume.

I hope it helps!

3 0
4 years ago
Ammonium phosphate NH43PO4 is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid H3PO4 with
mestny [16]

Answer:

The weight of ammonium phosphate is 10 gm

Explanation:

The chemical reaction of ammonium phosphate formation is as follows.

3NH_{3}+H_{3}PO_{4} \rightarrow [(NH_{4})_{3}PO_{4}]

From the reaction one mole of phosphoric acid is equivalent to the one mole of ammonium phosphate.

So, "n" mole of phosphoric acid is equivalent to the "n" mole of ammonium phosphate.

Number of moles in 7.1 grams of phosphoric acid = \frac{7.1}{Molarmass\,of phosphoric\,acid}

\frac{7.1}{98}= \frac{1}{13.8}

<u>Formation weight of ammonium phosphate :</u>

Weight of ammonium phosphate = = \frac{1}{13.8}\times Molarmass\,of\,\,ammonium\,phosphate

=\frac{149}{13.8} = 10.79gm

Round the answer to 2 significant digits

Weight of ammonium phosphate = 10 gm

7 0
3 years ago
When water vapor cools it condenses select the number that represents this process on the diagram
TiliK225 [7]
2 is the correct answer.
6 0
4 years ago
Read 2 more answers
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