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VashaNatasha [74]
3 years ago
10

A uniform electric field of magnitude 144 kV/m is directed upward in a region of space. A uniform magnetic field of magnitude 0.

38 T perpendicular to
Physics
1 answer:
snow_lady [41]3 years ago
7 0

Complete Question

A uniform electric field of magnitude 144 kV/m is directed upward in a region of space. A uniform magnetic field of magnitude 0.38 T perpendicular to the electric field also exists in this region. A beam of positively charged particles travels into the region. Determine the speed of the particles at which they will not be deflected by the crossed electric and magnetic fields. (Assume the beam of particles travels perpendicularly to both fields.)

Answer:

The velocity is  v =  3.79 *10^{5} \ m/s  

Explanation:

From the question we are told that

    The  magnitude of the electric field is  E  =  144 \ kV /m   =  144*10^{3} \  V/m

     The magnetic field is  B  =  0.38 \ T

   

The force due to the electric field is mathematically represented as

      F_e =  E  * q

and

The force due to the magnetic field is mathematically represented as

    F_b  =  q * v  *  B * sin(\theta )

Now given that it is perpendicular ,  \theta  = 90

=>   F_b  =  q * v  *  B * sin(90)

=>   F_b  =  q * v  *  B

Now  given that it is not deflected it means that

        F_ e  =  F_b

=>    q *  E = q *  v  * B

=>   v =  \frac{E}{B }

 substituting values

     v =  \frac{ 144 *10^{3}}{0.38 }

     v =  3.79 *10^{5} \ m/s

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The electron affinity of thulium has been measured by a technique known as laser photodetachment electron spectroscopy. In this
antoniya [11.8K]

Answer:

ΔE = 1.031 eV

Explanation:

For this exercise let's calculate the energy of the photons using Planck's equation

          E = h f

wavelength and frequency are related

         c = λ f

         f = c /λ

let's substitute

         E = h c /λ

let's calculate

         E = 6.63 10⁻³⁴ 3 10⁸/1064 10⁻⁹

         E = 1.869 10⁻¹⁹ J

let's reduce to eV

         E = 1.869 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)

        E = 1.168 eV

therefore the electron affinity is

         ΔE = E - 0.137

         ΔE = 1.168 - 0.137

         ΔE = 1.031 eV

3 0
3 years ago
Does anyone know this
NARA [144]

1) The net force is 16 N to the right

2) The net force is 98 N to the left

3) The net  force is 0.5 N downward

4) The net force is 170 N to the right

5) The net force is 175 N to the  right

Explanation:

1)

To find the net force, we have to analyze all the forces acting on the box.

We have:

  • Force to the right: F_a = 20 N, the applied force
  • Force to the left: F_f = 4 N, the force of friction
  • Force to the bottom: F_g = 400 N, the weight of the box (the weight is always downward vertically)
  • Force to the top: F_N = 400 N. This is the normal force, which is the reaction force exerted by the table on the box: it points upward and counterbalances the weight of the box, preventing it from falling down)

Therefore, the horizontal net force is

F_x = F_a - F_f = 20 - 4 = 16 N (to the right)

While the vertical force is

F_y = F_N - F_g = 400 - 400 = 0

So the net force is 16 N to the right.

2)

In this case, we have the following forces:

  • F_g = 4 N downward, the weight of the ball
  • F_a = 100 N to the left, the force that kicks the ball
  • F_f = 2 N to the right, the force of friction
  • F_N = 4 N upward, the normal reaction exerted by the field on the ball

Therefore, the horizontal net force is

F_x =F_a - F_f = 100 -2 = 98 N (to the left)

While the vertical force is

F_y = F_g - F_N = 4 - 4 = 0 (downward)

And so, the net force is 98 N to the left.

3)

The force acting on the squirrel in this problem are:

  • F_g = 8 N downward, the weight of the squirrel
  • F_f = 7.5 N upward, the air resistance, acting upward

Both forces act vertically and there are no other forces acting in other directions, therefore the net force on the squirrel is simply equal to the net force on the vertical direction, which is:

F_y = F_g - F_f = 8 - 7.5 = 0.5 N

And since the weight is larger than the air resistance, the direction of the net force is downward.

4)

The forces acting on Monkey are:

  • F_1=95 N is the force applied to the right by Bunny
  • F_2 = 75 N is the force applied by Deer from the left (so, also on the right)
  • F_g = 50 N is the weight of Monkey, downward
  • F_N = 50 N is the normal reaction exerted by the surface, upward

So, the net force in the horizontal direction is

F_x = F_1 + F_2 = 95+75=170 N (to the right)

While the net force in the vertical direction is

F_y = F_N - F_g = 50 - 50 = 0

And therefore the net force is 170 N to the right

5)

The forces acting on Deer are:

  • F_a = 100 N + 100 N = 200 N to the right, the combined force applied by Bunny and Monkey
  • F_f = 25 N to the left, the force of friction
  • F_g = 150 N downward, the weight of the deer
  • F_N = 150 N upward, the normal reaction from the surface that balances the weight

So the net horizontal force is

F_x = F_a - F_f = 200 - 25 = 175 N to the right

While the net vertical force is

F_y = F_N - F_g = 150 - 150 = 0

So the net force is 175 N to the right.

Learn more about vector addition:

brainly.com/question/4945130

brainly.com/question/5892298

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3 years ago
Describe how the ocean influences climate by storing heat and water? Give one example to justify your answer.
just olya [345]
The sun light that received by the water in the ocean will increase the average temperature of the water and make it warmer.
With the help of wind and current, the warm water will spread out to another region, and increasing the average temperature in that region and affecting its overall climate.
Example The temperature rise in Valdivia<span>, Chile and in Beijing, China after receiving warm water from arctic.</span>
7 0
4 years ago
3. A model rocket is launched straight upward at 58.8 m/s.
kolezko [41]

Answer:

a). 6 seconds

b). 12 seconds

c). 176.4 meters

Explanation:

a). Equation to be applied to calculate the time taken by the rocket to reach at the peak height,

   v = u - gt

where v = final velocity

u = initial velocity = 58.8 m per sec

g = gravitational pull = 9.8 m per sec²

t = duration of the flight

At the peak height,

v = 0

Therefore, 0 = 58.8 - (9.8)(t)

t =  \frac{58.8}{9.8}

 = 6 seconds

b). Total time of flight = 2(Time taken to go up)

                                    = 2×6

                                    = 12 sec

c). Formula to get the peak height is,

   h=ut-\frac{1}{2}gt^2

   h = (58.8)6 - \frac{1}{2}(9.8)(6)^2

      = 352.8 - 176.4

      = 176.4 meters

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4 years ago
There’s 5.68 s until the end of a "Red Light, Green Light" game, when "Green Light" is called. You start atrest and accelerate a
shutvik [7]

Answer:

SQUID game imagine

Explanation:

7 0
3 years ago
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