You are testing a new amusement park roller coaster with an empty car with a mass 120 kg. One part of the track is a vertical lo
1 answer:
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Answer:
t = √2y/g
Explanation:
This is a projectile launch exercise
a) The vertical velocity in the initial instants ( = 0) zero, so let's use the equation
y = t -1/2 g t²
y= - ½ g t²
t = √2y/g
b) Let's use this time and the horizontal displacement equation, because the constant horizontal velocity
x = vox t
x = v₀ₓ √2y/g
c) Speeds before touching the ground
vₓ = vox = constant
=
- gt
= 0 - g √2y/g
= - √2gy
tan θ = Vy / vx
θ = tan⁻¹ (vy / vx)
θ = tan⁻¹ (√2gy / vox)
d) The projectile is higher than the cliff because it is a horizontal launch
Answer:
300N
Explanation:
Given parameters:
Mass of car = 1500kg
Initial velocity = 0m/s
Distance covered = 45m
Time = 15s
Unknown:
Net force applied = ?
Solution:
From Newton's second law:
Force = mass x acceleration
Force = mass x
v is the final velocity
u is the initial velocity
t is the time taken
Final velocity = =3m/s
Force = 1500 x = 300N