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tatiyna
2 years ago
11

Water flows through a garden hose which is attached to a nozzle. The water flows through hose with a speed of 1.81 m/s and throu

gh the nozzle with a speed of 18.3 m/s. Calculate the maximum height (in m) to which water could be squirted if it emerges from the nozzle and emerges with the nozzle removed. (a) Emerges from the nozzle. m (b) Emerges with the nozzle removed, assuming the same flow rate. m
Physics
1 answer:
Serggg [28]2 years ago
6 0

Answer:

a) 17.086m

b) 0.1671 m

Explanation:

Given data: speed of water through the hose  = 1.81 m/s

through the nozzle = 18.3 m/s

We know that maximum height of an object with upward velocity v is given by,

a) H = v^2/2g

where H is the maximum height water emerges  

= 18.3^2/(2×9.8) = 17.086 m answer

b) Again,  

H = v^2/2g

= 1.81^2/(2×9.8) = 0.1671 m

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Therefore;

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For a person left behind on the platform, we have that the radio source is receding, therefore, we have;

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(1) Given that (v + v_s) > v, therefore, v < (v + v_s), f' < f, the frequency heard by the person left on the platform, f', is smaller (lower) than the frequency produced by the radio

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For the the person down below on the rubber raft, the radio source is advancing

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(2) The frequency is not constant as the speed of the source is increasing while it under the acceleration due to gravity

(3) During the fall, the speed of the source continuously increases under the effect of gravitational attraction and therefore the frequency heard by the person on the platform becomes progressively greater (higher)

Explanation:

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