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Ad libitum [116K]
4 years ago
9

200 gallon tank fills at 3 gallons/minute and loses 2 gallons/minute how long does it take to fill up

Mathematics
1 answer:
goblinko [34]4 years ago
7 0

it fills at 3 gallons per minute, but loses 2 gallons per minute

 3-2 =1, so it fills at 1 gallon per minute

200 gallons at 1 gallon per minute = 200 minutes,

200/60 = 3 hours and 20 minutes

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QS¯¯¯¯¯¯¯ bisects ∠PQR . If m∠PQS = 5x and m∠RQS = 2x + 6, then what is m∠PQR ? m∠PQR is
soldi70 [24.7K]

Answer:

PQR = 20

Step-by-step explanation:

Given

Bisector: QS

PQS = 5x

RQS = 2x + 6

Required

Determine PQR

Since PQR is bisected to PQS and RQS, we have that

PQS = RQS

Substitute expressions for PQS and RQS

5x = 2x + 6

Collect Like Terms

5x - 2x = 6

3x = 6

Divide both sides by 3

x = 2

Solving for PQR;

PQR = PQS + RQS

PQR = 5x + 2x + 6

PQR = 7x + 6

Substitute 2 for x

PQR = 7 * 2 + 6

PQR = 14 + 6

PQR = 20

4 0
4 years ago
A geometric series has second term 375 and fifth term 81 . find the sum to infinity of series .
Eduardwww [97]

Answer:  \bold{S_{\infty}=\dfrac{3125}{2}=1562.5}

<u>Step-by-step explanation:</u>

  a₁,  375,  a₃,   a₄,  81

First, let's find the ratio (r). There are three multiple from 375 to 81.

375r^3=81\\\\r^3=\dfrac{81}{375}\\\\\\r^3=\dfrac{27}{125}\qquad \leftarrow simplied\\\\\\\sqrt[3]{r^3} =\sqrt[3]{\dfrac{27}{125}}\\ \\\\r=\dfrac{3}{5}

Next, let's find a₁

a_1\bigg(\dfrac{3}{5}\bigg)=375\\\\\\a_1=375\bigg(\dfrac{5}{3}\bigg)\\\\\\a_1=125(5)\\\\\\a_1=625

Lastly, Use the Infinite Geometric Sum Formula to find the sum:

S_{\infty}=\dfrac{a_1}{1-r}\\\\\\.\quad =\dfrac{625}{1-\frac{3}{5}}\\\\\\.\quad =\dfrac{625}{\frac{2}{5}}\\\\\\.\quad = \dfrac{625(5)}{2}\\\\\\.\quad = \large\boxed{\dfrac{3125}{2}}

7 0
3 years ago
The equation of a line is given below.
Yanka [14]

Answer:

Please mark as Brainliest :)

Step-by-step explanation:

7 0
3 years ago
A new centrifugal pump is being considered for an application involving the pumping of ammonia. The specification is that the fl
ollegr [7]

Answer:

from the t-distribution table, at df = 7 and t = 2.23

Lies p-values [ 0.05 and 0.025 ]

Hence;

0.025 < p-value < 0.05

Step-by-step explanation:

Given that;

x^{bar} = 6.5 gpm

μ = 5 gpm

n = eight runs = 8

standard deviation σ = 1.9 gpm

Test statistics;

t = (x^{bar} - μ) / \frac{s}{\sqrt{n} }

we substitute

t = (6.5 - 5) / \frac{1.9}{\sqrt{8} }

t = 1.5 / 0.67175

t = 2.23

the degree of freedom df = n-1 = 8 - 1

df = 7

Now, from the t-distribution table, at df = 7 and t = 2.23

Lies p-values [ 0.05 and 0.025 ]

Hence;

0.025 < p-value < 0.05

3 0
3 years ago
What is the value of fraction 1 over 2x3 + 5.3y, when x = 2 and y = 3? 8.3 9.3 18.9 19.9
Fantom [35]
?        sorry, its hard to understand                                                    
6 0
4 years ago
Read 2 more answers
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