Answer:
If T^2 = a^3
T1^2 / T2^2 = a1^3 / a2^3
Or T2^2 = T1^2 * ( a2^3 / a1^3)
Given T1 = 1 yr and a2 / a1 = 17
Then T2^2 = 1 * 17^3
or T2 = 70 yrs
Answer:
Part(a): The final angular velocity is
Part(b): The ratio of the rotational energies is ,showing the the energy of th system will decrease.
Explanation:
Part(a):
If '' be the moment of inertia of an object and '' be its angular velocity then the angular momentum '' of the object can be written as
If '' and '' be the moment of inertia of the two cylinders and '' and '' be the initial angular velocity of the cylinders and '' and '' be their respective final angular velocity, then from conservation of angular momentum,
Given, . From the above expression
Part(b):
Initial kinetic energy
and Final kinetic energy
Substituting the value of ,
The above expression shows that the ebergy of the system will decrease.
Answer:
According to the right-hand rule, the magnetic field is into the page.
Explanation:
According to the right-hand rule, the magnetic field is into the page. According to this rule, if the middle finger points in the direction of initial motion of the charge as it enters the magnetic field to the right, and point the thumb and index finer perpendicular to each other and the middle finer perpendicular to the index finer. We then point the middle finger to the right in the direction of motion of the proton. If we are to have a clockwise force on the proton in the plane of the page, the thumb must point parallel to the page, downwards towards the south. The direction of the index finger is thus the direction of the magnetic field, and this is into the page.
transparent --> translucent --> opaque
A. Is the correct answer
Answer:
0.0195 m
Explanation:
= density of hockey puck = 9.45 gcm⁻³ = 9450 kgm³
= diameter of hockey puck = 13 cm = 0.13 m
= height of hockey puck = 2.8 cm = 0.028 m
= density of mercury = 13.6 gcm⁻³ = 13600 kgm³
= depth of puck below surface of mercury
According to Archimedes principle, the weight of puck is balanced by the weight of mercury displaced by puck
Weight of mercury displaced = Weight of puck