<span>Miller Urey experiment's purpose was to test the chemical origin of life under the conditions supposed to be present on the early Earth.
</span>The scientists Miller and Urey heated a mixture of water<span>, </span>ammonia<span>, </span>methane<span> and </span>hydrogen<span> in a sterile flask until it evaporated water to produce water vapour. </span><span>Electric sparks were passed through the mixture of </span>water vapour and gases, simulating lightning. The experiment was done during one week. After a week, the contents were analysed and Miller and Uray proved that <span>several organic compounds could be formed spontaneously by simulating the conditions of Earth's early atmosphere.</span>
Answer:
In both cases the height is greater than 10.3 m
Explanation:
Pressure is defined by the relationship
P = F / A
in this case the force is the weight of the two gases
F = W = m g
If we use the definition of density
ρ = m / V
V = A h
m = ρ A h
we substitute
P = ρ g h
h = 
For this case the density of the gases is
ρ' = 0.9
h =
we calculate
ρ’= 0.9 \rho_{water}
h = 1 105 / (0.9 1000 9.8)
h = 11.3 m
ρ’= 0.8 \rho_{water}
h = 1 105 / (0.8 1000 9.8
h = 12.8 m
In both cases the height is greater than 10.3 m
The second ball traveled a greater distance when compared to the first ball because the second ball spent more time in motion.
The given parameters;
- time of fall of the first ball, t = 1 s
- time of fall of the second ball, t = 3 s
The distance traveled by each ball is calculated using the second equation of motion as shown below.
The distance traveled by the first ball is calculated as follows;

The distance traveled by the second ball is calculated as follows;

Thus, the second ball traveled a greater distance because it spent more time in motion.
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Answer:
we have to find out the critical resolved shear stress. As it it given in the question
Ф = 28.1°and the possible values for λ are 62.4°, 72.0° and 81.1°.
a) Slip will occur in the direction where cosФ cosλ are maximum. Cosine for all possible λ values are given as follows.
cos(62.4°) = 0.46
cos(72.0°) = 0.31
cos(81.1°) = 0.15
Thus, the slip direction is at the angle of 62.4° along the tensile axis.
b) now the critical resolved shear stress can be find out by the following equation.
τ
= σ
( cosФ cosλ)
now by putting values,
= (1.95MPa)[ cos(28.1) cos(62.4)] = 0.80 MPa (114 Psi) 7.23
To solve this problem we will use Newton's second law in order to obtain the weight of a person. The second law tells us that
F = ma
Where,
m = mass
a = Acceleration
In this particular case, the acceleration is equal to that exerted by the earth through gravitational acceleration, so if the person's weight is 75Kg and the gravity is
, the weight of the body will be,



When the elevator is at rest this reads 735.75N and 75Kg (The same mass of the person)