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4 years ago

2 QUESTIONS 20 POINTS

Physics

2 answers:

irina [24]4 years ago

7 0

I think 1 is x-rays and 2 is ultraviolet light.. I'm not that sure

stich3 [128]4 years ago

3 0

Just finished completitng this kind of info in the course that I am taking! X-rays contain the most energy, and microwaves would have the longest wavelength.

Higher frequency= more energy

If you want to add it to your notes, this is EMR listed in order from highest frequency/highest energy, to lowest frequency/ lowest energy.

Gamme rays, X-rays, UV, Visible light, Infrared, Microwave, and radio waves.

So, Gamme rays have the highest energy and frequency, and radio waves havethe lowest.

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Two people are talking at a distance of 3.0 m from where you are and you measure the sound intensity as 1.1 × 10-7 W/m2. Another

ioda

Answer:

$6.1875\times 10^{-8}$

Explanation:

Assuming uniform spread of sound with no significant reflections or absorption. We know that sound intensity varies $I=\frac {k}{r^{2}}$ where r is the distance

Since intensity is given then when at 3 m

$1.1\times 10^{-7}= \frac {k}{3^{2}}$

$k=3^{2}\times 1.1\times 10^{-7}= 9.9\times 10^{-7}$

Since we have the constant then at 4m

Intensity, $I= \frac {9.9\times 10^{-7}}{4^{2}}=6.1875\times 10^{-8}$

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3 years ago

What would happen to the seasons if the Earth’s tilt was only 10 degrees and why? What about 50 degrees and why?

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Answer:

If it was only 10 degrees the seasonal changes would lessen and vise versa for 50. meaning the seasonal changes would become more extreme

Explanation:

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3 years ago

Three ways we can use an electric current

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To charge something or use experiments

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3 years ago

How do earthquakes affect boulders

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4 years ago

you are riding on a train traveling 80 km/h. if you walk toward the back of the train at a speed of 1.2 km/h relative to the tra

Mazyrski [523]

Answer:

Velocity of the passenger = 78.8[km/h]

Explanation:

In order to solve this problem, we must observe the train from a distant point of the train. In this way we can observe that the train moves at 80[km/h] relative to the ground.

In such a way that the passenger moves in a direction contrary to the movement of the train.

$v_{pass}=80-1.2\\ v_{pass}=78.8[km/h]$

The Observer located outside the train will see how the passenger moves away at 78.8 [km / h] and not at 80[km/h] which is the speed of the train.

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3 years ago