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3 years ago

What will happen to the density of an object when it's mass increases?

2 answers:

const2013 [10]3 years ago

7 0

"Increase its mass" usually means just get more of it, and its size increases too.
When that happens, the density doesn't change.

But if you have some way to increase its mass but not let it get any bigger,
then its density would increase.

An example of that might be: Take a jar or tank of air, and pump more air
into it. You added more mass of air, but the size remained the same. Then
the density of the gas in the tank increased.

ioda3 years ago

4 0

The density will decrease...its pretty logical

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An air-filled parallel-plate capacitor is constructed with a plate area of 0.40 m2 and a plate separation of 0.10 mm. It is then

seropon [69]

Answer:

The charge stored is $Q = 4.25 *10^{-7 } \ C$

The energy stored is $E = 2.55*10^{-6} \ J$

Explanation:

From the question we are told that

The area of the plates is $A = 0.40 \ m^2$

The separation between the plate is $d = 0.10 \ mm =0.0001 \ m$

The potential difference is $V = 12 \ V$

The permitivity of free space is $\epsilon_o = 8.85 *10^{-12} C^2 \cdot N^{-1} \cdot m^2$

The dielectric constant of glass is K = 5.0

Generally the capacitance of this capacitor is

$C = \frac{\epsilon_o * A}{d}$

substituting values

$C = \frac{8.85*10^{-12} * 0.40}{0.0001}$

$C = 3.34 *10^{-8} \ C$

The charge stored is mathematically evaluated as

$Q = CV$

substituting values

$Q = (3.54*10^{-8} * 12)$

$Q = 4.25 *10^{-7 } \ C$

The energy stored is

$E = 0.5 * CV^2$

substituting values

$E = 0.5 * (4.25 *10^{-7} * 12^2)$

$E = 2.55*10^{-6} \ J$

7 0

3 years ago

Which best describes the two main functions of transistors in circuits? resisting and amplifying measuring and switching resisti

Marizza181 [45]

The two main function of a transistor is to amplify or switch electronic signals. The switch is two options: on / off. The amplification function is a change in voltage.

8 0

3 years ago

You are standing in a building whose height (40m) you throw a ball downward at a angle of -30 at a speed of (10m/s) acceleration

jeyben [28]

Answer: 3.41 s

Explanation:

Assuming the question is to find the time $t$ the ball is in air, we can use the following equation:

$y=y_{o}+V_{o}sin \theta t-\frac{1}{2}gt^{2}$

Where:

$y=0m$ is the final height of the ball

$y_{o}=40 m$ is the initial height of the ball

$V_{o}=10 m/s$ is the initial velocity of the ball

$t$ is the time the ball is in air

$g=9.8 m/s^{2}$ is the acceleration due to gravity

$\theta=30\°$

Then:

$0 m=40 m+(10 m/s)(sin(30\°))t-\frac{1}{2}9.8 m/s^{2}t^{2}$

$0 m=40 m+5m/s t-4.9 m/s^{2}t^{2}$

Multiplying both sides of the equation by -1 and rearranging:

$4.9 m/s^{2}t^{2}-5m/s t-40 m=0$

At this point we have a quadratic equation of the form $at^{2}+bt+c=0$ , which can be solved with the following formula:

$t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$

Where:

$a=4.9$

$b=-5$

$c=-40$

Substituting the known values:

$t=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(4.9)(-40)}}{2(4.9)}$

Solving the equation and choosing the positive result we have:

$t=3.41 s$ This is the time the ball is in air

5 0

3 years ago

In which region of the electromagnetic spectrum is most of earth's outgoing terrestrial radiation?

Bond [772]

The answer is Infrared. The infrared of the electromagnetic spectrum is most of earth's outgoing terrestrial radiation. <span>Earth is the hot body with temperature of 30 degrees on the average.</span>

6 0

3 years ago

Need help on this please

Ratling [72]

question 2 answer is ALL OF THE ABOVE

question 3 answer is WARM AND MOIST.

8 0

3 years ago