The quadrilaterals whose consecutive and opposite angles are always congruent are the square and the rectangle. All of the angles of the square and the rectangle are 90 degrees. The consecutive angles of the parallelogram and the rhombus are not equal.
By looking at it, I can tell the second expression is greater due to a a large postive number that's being added to it. Let's solve.
-12+6=-6-4=-10
-34-3=-37+39=2
So, -34-3+39 is greater.
This is just the answer digitally i cant explain the process
