Ask question

Ask question

All categories

3 years ago

8

Which of the following adaptations would you expect tofind in an animal in the alpine biome, but not in the taiga

2 answers:

kvasek [131]3 years ago

8 0

Answer:

I think the best answer is migration. In an alpine biome, animals have two problems which is the very cold temperature and the UV rays from the sun. Most alpine animals hibernate and migrate to warmer areas of the mountains when the temperature continues to drop.

almond37 [142]3 years ago

7 0

I think the best answer is migration. In an alpine biome, animals have two problems which is the very cold temperature and the UV rays from the sun. Most alpine animals hibernate and migrate to warmer areas of the mountains when the temperature continues to drop.

You might be interested in

when an inflated Balloon in rubbed against the wall ,it sticks to the wall for a while why give reason

ira [324]

Answer:

the reason is because of friction

3 0

3 years ago

An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respective

djverab [1.8K]

Answer:

The new partial pressures after equilibrium is reestablished for $PCl_3$ :

$P_1'=6.798 Torr$

The new partial pressures after equilibrium is reestablished $Cl_2$ :

$P_2'=26.398 Torr$

The new partial pressures after equilibrium is reestablished for $PCl_5$ :

$P_3'=223.402 Torr$

Explanation:

$PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)$

At equilibrium before adding chlorine gas:

Partial pressure of the $PCl_3=P_1=13.2 Torr$

Partial pressure of the $Cl_2=P_2=13.2 Torr$

Partial pressure of the $PCl_5=P_3=217.0 Torr$

The expression of an equilibrium constant is given by :

$K_p=\frac{P_1}{P_1\times P_2}$

$=\frac{217.0 Torr}{13.2 Torr\times 13.2 Torr}=1.245$

At equilibrium after adding chlorine gas:

Partial pressure of the $PCl_3=P_1'=13.2 Torr$

Partial pressure of the $Cl_2=P_2'=?$

Partial pressure of the $PCl_5=P_3'=217.0 Torr$

Total pressure of the system = P = 263.0 Torr

$P=P_1'+P_2'+P_3'$

$263.0Torr=13.2 Torr+P_2'+217.0 Torr$

$P_2'=32.8 Torr$

$PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)$

At initail

(13.2) Torr (32.8) Torr (13.2) Torr

At equilbriumm

(13.2-x) Torr (32.8-x) Torr (217.0+x) Torr

$K_p=\frac{P_3'}{P_1'\times P_2'}$

$1.245=\frac{(217.0+x)}{(13.2-x)(32.8-x)}$

Solving for x;

x = 6.402 Torr

The new partial pressures after equilibrium is reestablished for $PCl_3$ :

$P_1'=(13.2-x) Torr=(13.2-6.402) Torr=6.798 Torr$

The new partial pressures after equilibrium is reestablished $Cl_2$ :

$P_2'=(32.8-x) Torr=(32.8-6.402) Torr=26.398 Torr$

The new partial pressures after equilibrium is reestablished for $PCl_5$ :

$P_3'=(217.0+x) Torr=(217+6.402) Torr=223.402 Torr$

5 0

3 years ago

If the collected information showed that the temperature was 10°C and the wind speed was 75 mph, what type of weather would it

Shkiper50 [21]

Answer:

cold and windy

Explanation:

if its 10 degrees outside then it must be cold. then 75 mph that is very windy

4 0

2 years ago

What do you think is the primary reason why the Unionid mussel population declined whenever there is a dramatic increase in the

igomit [66]

Answer:

When the Zebra arrived they ate all the food so the Unionid mussels declined as they died from the lack of food. Causing the Zebra Zebra numbers to increase and Unionid numbers to decline.

4 0

3 years ago

The term element refers to atoms that have the same number of _______.

erica [24]

I guess it’s Electrons

7 0

3 years ago

Read 2 more answers