Answer:
2NaHCO3 + H2SO4 -----> Na2SO4 + 2H2O + 2CO2.
Explanation:
Answer:
hello your question lacks the required reaction pairs below are the missing pairs
Reaction system 1 :
A + B ⇒ D ![-r_{1A} = 10exp[-8000K/T]C_{A}C_{B}](https://tex.z-dn.net/?f=-r_%7B1A%7D%20%20%3D%2010exp%5B-8000K%2FT%5DC_%7BA%7DC_%7BB%7D)
A + B ⇒ U 
Reaction system 2
A + B ⇒ D 
B + D ⇒ U 
Answer : reaction 1 : description of the reactor system : The desired reaction which is the first reaction possess a higher activation energy and higher temperature is required to kickstart reaction 1
condition to maximize selectivity : To maximize selectivity the concentration of reaction 1 should be higher than that of reaction 2
reaction 2 :
description of reactor system : The desired reaction i.e. reaction 1 has a lower activation energy and lower temperatures is required to kickstart reaction 1
condition to maximize selectivity:
to increase selectivity the concentration of D should be minimal
Explanation:
Reaction system 1 :
A + B ⇒ D ![-r_{1A} = 10exp[-8000K/T]C_{A}C_{B}](https://tex.z-dn.net/?f=-r_%7B1A%7D%20%20%3D%2010exp%5B-8000K%2FT%5DC_%7BA%7DC_%7BB%7D)
A + B ⇒ U 
the selectivity of D is represented using the relationship below
hence SDu = 1/10 * 
description of the reactor system : The desired reaction which is the first reaction possess a higher activation energy and higher temperature is required to kickstart reaction 1
condition to maximize selectivity : To maximize selectivity the concentration of reaction 1 should be higher than that of reaction 2
Reaction system 2
A + B ⇒ D 
B + D ⇒ U 
selectivity of D

hence Sdu = 
description of reactor system : The desired reaction i.e. reaction 1 has a lower activation energy and lower temperatures is required to kickstart reaction 1
condition to maximize selectivity:
to increase selectivity the concentration of D should be minimal
True. The prototype is usually the "rough draft" the figure out what needs fixed or upgraded before they make the final product "final draft". Hope that helped!
Your answer would be answer choice D. The ball is accelerating as the velocity is increasing at a constant rate.
Hope this helps,
♥<em /><em>A.W.E.<u>S.W.A.N.</u></em>♥
<span>Ca(NO3)2 + Na2CO3 = CaCO3 + 2NaNO3
Yes a precipitate of Calcium Carbonate is formed since it is insoluble in water.
Mol Wt of Calcium Nitrate is 164. And that of Calcium Carbonate is 100.
One mole of Calcium Nitrate produces one mole of Calcium Carbonate.
i.e. 164 gms will produce 100gms of precipitate
So, 1.74gms of Calcium Carbonate will be obtained from 2.85gms Calcium Nitrate present in the original solution.</span>