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3 years ago

Can somebody that is good at science help me with these two questions? Please and thank you!

Chemistry

1 answer:

laiz [17]3 years ago

8 0

1. The forces make the train float because the poles are the same on each side causing them to repell (north and north repell)

2. B is more stable. If you pushed A it would fall and that would cause more disturbance

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A person runs 500 ft in 50 seconds how fast are they moving

Nezavi [6.7K]

10 miles per hour because 500 divided by 50 is 10

8 0

3 years ago

Read 2 more answers

Is the osmotic pressure of a 0.10 M solution of NaCl greater than, less than, or equal to that of a 0.10 M solution of KBr?a. eq

jonny [76]

Answer:

a. equal to

Explanation:

The osmotic pressure is calculated by the formula:

π = i * M * R * T

Where π is the osmotic pressure, M is the concentration, R is a constant, T is temperature and i is the van't Hoff's factor (the number of ions a compound forms when dissolved in water, for both NaCl and KBr is 2).

Because R is always the same, and Temperature and Concentration are equal between the two solutions, the osmotic pressure of both solutions are also equal.

4 0

3 years ago

pls help!!! Calculate the pH of a solution with a H+ ion concentration of 2.6 x 10^-7 and round your answer to the nearest hundr

earnstyle [38]

Answer:

6.59

Explanation:

pH=-log[H+]

=-log[2.6×10^-7]

=6.59

8 0

2 years ago

Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibriumdescribed by the equation N2O4(g)↔

Vilka [71]

Answer : The correct option is, (C) 1.1

Solution : Given,

Initial moles of $N_2O_4$ = 1.0 mole

Initial volume of solution = 1.0 L

First we have to calculate the concentration $N_2O_4$ .

$\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}$

$\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M$

The given equilibrium reaction is,

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

Initially c 0

At equilibrium $(c-c\alpha)$ $2c\alpha$

The expression of $K_c$ will be,

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

$K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}$

where,

$\alpha$ = degree of dissociation = 40 % = 0.4

Now put all the given values in the above expression, we get:

$K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}$

$K_c=\frac{(2\times 1\times 0.4)^2}{(1-1\times 0.4)}$

$K_c=1.066\aprrox 1.1$

Therefore, the value of equilibrium constant for this reaction is, 1.1

4 0

2 years ago

True or false natural elements don't reflect light.

Burka [1]

I think the statement is false. Natural elements do reflect light. Almost everything in this world reflect light. Reflection is when light bounces off an object. Hope this answers the question. Have a nice day.

3 0

3 years ago