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3 years ago

Solve for x in terms of p and a 2x+a=p

Mathematics

2 answers:

yan [13]3 years ago

6 0

2x =p-a
X=p/2 - a/2
X=p-a and 2

Masteriza [31]3 years ago

3 0

2x+a=p

2x=p-a

x=p-a/2

I hope I was able to help. Best of luck.

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Problem 3

Ilia_Sergeevich [38]

Problem 1 Answer: $x=10$

Simplify both sides of the equation

$(2)(x)+(2)(-3)=14(Distribute)$

$2x+-6=14$

$2x-6=14$

Add 6 to both sides

$2x-6+6=14+6$

$2x=20$

Divide both sides by 2

$2x/2=20/2$

$x=10$

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Problem 2 Answer: $x=-7$

Simplify both sides of the equation

$(-5)(x)+(-5)(-1)=40(Distribute)$

$-5x+5=40$

Subtract 5 from both sides

$-5x+5-5=40-5$

$-5x=35$

Divide both sides by -5

$-5x/5=35/-5$

$x=-7$

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Problem 3 Answer: $x=-8$

Simplify both sides of the equation

$(12)(x)+(12)(10)=24(Distribute)$

$12x+120=24$

Subtract 120 from both sides

$12x+120-120=24-120$

$12x=-96$

Divide both sides by 12

$12x/12=-96/12$

$x=-8$

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Problem 4 Answer: $x=-1/2$

Move all terms to the left:

$2(x+6)-(11)=0$

Multiply parentheses

$2x+12-11=0$

Add all the numbers together, and all the variables

$2x+1=0$

Move all terms containing x to the left, all other terms to the right

$2x=-1\\x=-1/2$

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Problem 5 Answer: $x = 44$

3 0

3 years ago

Read 2 more answers

PLEASE HELP! Reduce to simplest form. 5/8 - (- 7/2)

Daniel [21]

Answer:

$\huge\boxed{\sf 4\frac{1}{8} }$

Step-by-step explanation:

$\sf =\frac{5}{8} - (-\frac{7}{2} )\\\\Rule : ( - *- = +)\\\\\=\frac{5}{8} +\frac{7}{2} \\\\LCM = 8\\\\\=\frac{5+28}{8} \\\\\=\frac{33}{8} \\\\=4\frac{1}{8}$

$\sf =\frac{5}{8}+ \frac{7}{2} \\\\=\frac{5+28}{8}$

$\sf =\frac{33}{8} \\\\=4\frac{1}{8}$

Hope this helped!

<h2>~AnonymousHelper1807</h2>

7 0

3 years ago

How many terms are in 5x4-2x3+x-4

san4es73 [151]

I think that there are 4 termms if we condider onlu plus and minus as operators.

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3 years ago

What is the solution to an equation /

navik [9.2K]

Answer:

Idk what u mean?

Step-by-step explanation:

but i searched it up and here are my results

The solution of an equation is the set of all values that, when substituted for unknowns, make an equation true. For equations having one unknown, raised to a single power, two fundamental rules of algebra, including the additive property and the multiplicative property, are used to determine its solutions.Mar 20, 2020

email me if it helps

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3 years ago

Which side lengths represent the sides of a right triangle? A) 1, 1, 2 B) 2, 3, 5 C) 8, 6, 10 D) 12, 16, 21

Bingel [31]

Is there a pic of the graph

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3 years ago

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