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KIM [24]
3 years ago
15

What is the difference between mass and weight?

Physics
1 answer:
I am Lyosha [343]3 years ago
5 0
Mass is the actual amount of material contained in a body and is measured by kg, gm, etc. Whereas weight is the force extorted by the gravity on that object mg. Note that mass is independent of everything but weight is different on earth, moon, etc.

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As the temperature of an object increases, the wavelength of the brightest light emitted _______
alexira [117]

Answer:

option (B) decreases

Explanation:

According to the Wein's displacement law, the minimum wavelength of the radiated emission is inversely proportional to the absolute temperature of the body which emits radiation.

\lambda_{m}\alpha \frac{1}{T}

Where, T is the absolute temperature of the body and λm is the minimum wavelength of heat radiated.

Here, as the temperature increases, the wavelength decreases.

4 0
3 years ago
Which question could be tested in a scientific manner?
andrey2020 [161]
The questions from this lot which could be tested in a scientific manner would be "what causes some people to be color-blind"
and
"what are the best shoes to wear when exercising"
Both of these questions can be tested in a scientific way through an experiment. 
5 0
3 years ago
What is velocity? why is it important?​
Setler [38]

Answer:

<em>Velocity is the rate at which the position changes</em>

<em>Velocity is the rate at which the position changesWhy do we need</em>

<em>Velocity is the rate at which the position changesWhy do we needVectors make it convenient to handle quantities going in different directions</em><em>.</em><em>.</em><em> </em>

Explanation:

Thank you!

5 0
2 years ago
Read 2 more answers
A vacuum cleaner produces sound with a measured sound level of 75.0 dB. (a) What is the intensity of this sound in W/m2? W/m2 (b
jonny [76]

Answer:

Part a)

I = 3.16 \times 10^{-5} W/m^2

Part b)

P_o = 0.162 Pa

Explanation:

Part a)

Level of sound = 75 dB

now we know that

L = 10 Log\frac{I}{I_0}

here we know that

I_0 = 10^{-12} W/m^2

now we have

75 = 10 Log(\frac{I}{10^{-12}})

I = 3.16 \times 10^{-5} W/m^2

Part b)

Intensity of sound wave is given as

I = \frac{1}{2}\rho A^2\omega^2 c

here we know that

A = \frac{P_o}{Bk}

so we have

I = \frac{1}{2}\rho(\frac{P_o}{Bk})^2\omega^2 c

I = \frac{1}{2}\rho P_o^2 \frac{c^3}{B^2}

now we know

\rho = 1.2 kg/m^3

c = 340 m/s

B = 1.4 \times 10^5 Pa

now we have

3.16 \times 10^{-5} = \frac{1}{2}(1.2)P_o^2\frac{340^3}{(1.4\times 10^5)^2}

P_o = 0.162 Pa

5 0
3 years ago
In a tug of war between Mrs. Brenneman and Mr. Schroedl seems at a standstill. Then Mrs. Brenneman tugs hard giving a force of 4
sergiy2304 [10]
He feels a 10 N to the left force moves. Yes ,he moves.
4 0
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