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3 years ago

Why does something rolling down a ramp have greater distance when it the ramp keeps getting higher?

1 answer:

6 0

Well the most basic reason why is because of gravity. it would slow down the object going higher since their is gravity pushing on that object. going down, the object would get pushed faster since gravity is making it go down. hope this helps

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Astronauts on a distant planet set up a simple pendulum of length 1.2 m. The pendulum executes simple harmonic motion and makes

Iteru [2.4K]

Answer:

If you use P = 2 * pi * (L / g)^1/2 for the period of the simple pendulum

g = 4 * pi^2 * 1.2 / 2.8^2 = 6.04 m/s2

Note: omega = 2 pi * f = 2 pi / P and omega = (g / L)^1/2

7 0

3 years ago

A client experiences difficulty in performing the prone iso-abs exercise. Which of the following should be suggested as an regre

attashe74 [19]

Answer:

a. Quadruped arm and opposite leg raise

Explanation:

A client experiences difficulty in performing the prone iso-abs exercise, because the regression is Quadruped arm and opposite leg raise.

Iso-abs exercise is a beginner exercise that stabilizes the core muscle. Press the hips together. Slowly lift the pelvis from the floor til the back is straight. Carry this position for the desired time or til proper form bcomes difficult to maintained.

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3 years ago

Which of the following statements accurately describes a pedigree chart?

Dmitry_Shevchenko [17]

The correct letter answer choice is A. We just finished up genetics in 8th grade science. You're welcome :)

8 0

3 years ago

Read 2 more answers

A driver enters a one-lane tunnel at 34.4 m/s. The driver then observes a slow-moving van 154 m ahead travelling (in the same di

navik [9.2K]

Answer:

Ans. B) 22 m/s (the closest to what I have which was 20.16 m/s)

Explanation:

Hi, well, first, we have to find the equations for both, the driver and the van. The first one is moving with constant acceleration (a=-2m/s^2) and the van has no acceletation. Let´s write down both formulas so we can solve this problem.

$X(van)=5.65t+154$

$X(driver)=34.4t+\frac{(-2)t^{2} }{2}$

or by rearanging the drivers equation.

$X(driver)=34.4t+t^{2}$

Now that we have this, let´s equal both equations so we can tell the moment in which both cars crashed.

$X(van)=X(driver)$

$5.65t+154=34.4t-t^{2}$

$0=t^{2} -(34.4-5.65)t+154$ $0=t^{2} -28.75t+154$

To solve this equation we use the following formulas

$t=\frac{-b +\sqrt{b^{2}-4ac } }{2a}$

Where a=1; b=-28.75; c=154

So we get:

$t=\frac{28.75 +\sqrt{(-28.75)^{2}-4(1)(154) } }{2(1)}=21.63s$ $t=\frac{28.75 -\sqrt{(-28.75)^{2}-4(1)(154) } }{2(1)}=7.12s$

At this point, both answers could seem possible, but let´s find the speed of the driver and see if one of them seems ilogic.

$V(driver)=V_{0} +at$ }

$V(driver)=34.4\frac{m}{s} -2\frac{m}{s^{2} } *(7.12s)=20.16\frac{m}{s}$ $V(driver)=34.4\frac{m}{s} -2\frac{m}{s^{2} } *(21.63s)=-8.86\frac{m}{s}$

This means that 21.63s will outcome into a negative speed, for that reason we will not use the value of 21.63s, we use 7.12s and if so, the speed of the driver when he/she hits the van is 20.16m/s, which is closer to answer A).

Best of luck

8 0

3 years ago

A 1kg skateboard sits at the top of a ramp 20 fr off the ground . How much potential energy does it have ?

Finger [1]

Answer:

196J

Explanation:

Given parameters:

Mass of skateboard = 1kg

Height off the ground = 20m

Unknown:

Potential energy = ?

Solution:

The potential energy is the energy due to the position of a body above the ground.

It is mathematically expressed as:

Potential energy = mass x acceleration due gravity x height

Potential energy = 1 x 9.8 x 20 = 196J

8 0

3 years ago