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3 years ago

What is the amount of mass in a given volume called?

Physics

2 answers:

mixer [17]3 years ago

8 0

Answer=Density

D=m/v (the mass in a given volume is the density)

Vlad [161]3 years ago

3 0

The equation for density is density=mass/volume.

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An earth satellite remains in orbit at a distance of 13300 km from the center of the earth. what is its period? the universal gr

iren [92.7K]

Given: Altitude of satellite r = 13,300 Km convert to meter

r = 1.33 x 10⁷ m

Universal Gravitational constant G = 6.67 x 10⁻¹¹ N.m²/Kg²

Mass of the earth Me = 5.98 x 10²⁴ Kg

Required: Period of satellite T = ?

Formula: F = ma; Centripetal acceleration ac = V²/r F = GMeMsat/r²

Velocity of satellite V = 2πr/T

equate T from all given equation.

F = ma

GMeMsat/r² = MsatV²/r cancel Msat and insert V = 2πr/T

GMe/r² = (2πr)²/rT² Equate T or period of satellite

T² = 4π²r³/GMe

T² = 39.48(1.33 X 10⁷ m)³/(6.67 x 10⁻¹¹ N.m²/Kg²)(5.98 x 10²⁴ Kg)

T² = 9.29 x 10²² m³/3.99 x 10¹⁴ m³/s²

T² = 232,832,080.2 s²

T = 15,258.84 seconds or (it can be said around 4.24 Hr)

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4 years ago

Which of the following is the most appropriate unit to describe the time you can drive a car based on the amount of gas?

vredina [299]

The answer is A. Minutes per gallon, because the independent quantity is the gallons

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3 years ago

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a water line starts the service with an altitude of 1200m over the sea level, what is the velocity of the water above 1050 m ove

Ilia_Sergeevich [38]

Answer:

Velocity = 94.85m/s

Explanation:

Given the following data ;

Height = 1200m

Vertical distance = 1050m

To find the time, we would use the second equation of motion;

$S = ut + \frac {1}{2}at^{2}$

Substituting into the equation, we have;

$1200 = 0(t) + \frac {1}{2}*9.8*t^{2}$

$1200 = 0 + 4.9*t^{2}$

$1200 = 4.9*t^{2}$

$t^{2} = \frac {1200}{4.9}$

$t = \sqrt{122.45}$

t = 11.07 secs

To find the velocity;

Mathematically, velocity is given by the equation;

$Velocity = \frac{distance}{time}$

Substituting into the above equation;

$Velocity = \frac{1050}{11.07}$

Velocity = 94.85m/s

Therefore, the velocity of the water above 1050 m over the sea level is 94.85m/s.

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3 years ago

The kinetic energy of a ball with a mass of 0.5 kg and a velocity of 10 m/s is

Arada [10]

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Additional information:

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