Answer:
¹⁰₄Be —> ¹⁰₃Li + ⁰₋₁β
Explanation:
To know which equation is unbalanced, we shall compare the mass number and atomic number of the reactant and product together. This is illustrated below:
¹²¹₅₀Sn —> ⁰₋₁β + ¹²¹₅₁Sb
121 = 0 + 121
121 = 121
50 = –1 + 51
50 = 51
Thus the above equation is balanced
¹⁹⁰₇₈Pt —> ¹⁸⁶₇₆Os + ⁴₂α
190 = 186 + 4
190 = 190
78 = 76 + 2
78 = 78
Thus, the above equation is balanced
¹⁰₄Be —> ¹⁰₃Li + ⁰₋₁β
10 = 10 + 0
10 = 10
4 = 3 + (–1)
4 = 3 – 1
4 = 2
Thus, the above equation is unbalanced.
²³⁸₉₂U —> ⁴₂α + ²³⁴₉₀Th
238 = 4 + 234
238 = 238
92 = 2 + 90
92 = 92
Thus, the above equation is balanced.
From the illustrations made above, only ¹⁰₄Be —> ¹⁰₃Li + ⁰₋₁β
Is unbalanced.
It would increase becuase it wouldn’t make sense if it decreased
Answer:
2 to 1
Explanation:
The reaction equation is given as:
2KHCO₃ → K₂CO₃ + CO₂ + H₂O
The conversion factor between the moles of KHCO₃ and K₂CO₃ is 2 to 1.
From the balanced chemical equation, we find out that;
2 moles of 2KHCO₃ will produce 1 mole of K₂CO₃.
So given any mole of either of the reactant or product, we can find the unknown.
The triple bonds are the shortest bonds. So the correct option is C.
<h3>What are bonds?</h3>
Chemical bonds are the bonds that are the attraction between ions or molecules that makes up compounds. There are different types of bonds They are covalent, ionic, hydrogen, electrostatic, etc.
A single bond is formed when only one electron is shared between atoms. As the same triple bonds are formed when there are three electrons shared between atoms. Triple bonds are the shortest because they have less strength.
Thus, the correct option is C. triple bonds are the shortest.
To learn more about Chemical bonds, refer to the below link:
brainly.com/question/13655260
#SPJ1
The side of each water molecule with the oxygen atom uncovered will be marginally negative.
The side of each water molecule with the hydrogen atoms uncovered will be marginally positive.
So the two Cl{-} particles will be pulled in to the biggest number of positive charges, which happen in the boxes on the upper right and lower left.
The two Na{+} particles will be pulled in to the biggest number of negative charges, which happen in the boxes on the upper left and lower right.
