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iren [92.7K]
3 years ago
13

A Brønsted-Lowry acid is a substance which produces a. hydroxide ions in aqueous solution. b. accepts protons from other substan

ces. c. donates protons to other substances. d. accepts hydronium ions from other substances. e. produces hydrogen ions in aqueous solution.
Chemistry
1 answer:
kompoz [17]3 years ago
5 0

Answer:

A Brønsted-Lowry acid is a substance which donates protons to other substances. (option c.)

Explanation:

For Brønsted-Lowry acids, are the ones that donates protons and bases, the ones that accepts H⁺ from others compounds.

In this reaction:

NH₃  +  HCl → NH₄Cl

The hydrocloridic acid donates the proton to ammonia to make ammonium chloride. So the HCl, is a Brønsted-Lowry acid while the ammonia is a base.

There are cases, like water that behaves as acid and base.

These compounds are called amphoteric because it can donate H⁺ or OH⁻ at the same time.

H₂O ⇄  H⁺  +  OH⁻

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The chemical equation below shows the burning of magnesium (Mg) with oxygen (O2) to form magnesium oxide
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Answer:

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Explanation:

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2 years ago
What are some compounds that are made from the element copper?
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Answer:

All of these compounds are made from the element copper. Copper Acetates, Cuprous Oxide, Cupric Oxide (otherwise know as black copper oxide), Cupric Chloride, Copper Oxychloride, Cuprous Chloride, Cupric Nitrate, Copper Cyanide.

Explanation:

Copper is considered an element. You can use copper for Jewelry, Table Tops, Sinks, Dark Chocolate, Leafy Greens, Lobster, Nuts and Seeds, Mushrooms, Oysters, Liver and etc other nutrience. Copper is an easily molded base metal that is often added to precious metals to improve their elasticity, flexibility, hardness, colour, and resistance to corrosion.

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2 years ago
A plant release it’s seed , but soon there after, the area seeds are in experiences a yearlong drought. How would the seeds most
SOVA2 [1]

Answer:

Plants will absorb water through their roots and release water as vapor into the air through these stomata. To survive in drought conditions, plants need to decrease transpiration to limit their water loss. Some plants that live in dry conditions have evolved to have smaller leaves and therefore fewer stomata.

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6 0
3 years ago
Describe a qualitative test for sulfate in alum crystals using ionic reactions of barium chloride (BaCl2)
Lady bird [3.3K]

A qualitative test for sulfate in alum crystals using ionic reactions of barium chloride (BaCl2) is given Ba²⁺(aq) + SO₄²⁻ (aq)  →   BaSO₄(s).

<h3>What is qualitative test?</h3>

Qualitative test measures changes in color, melting point, odor, reactivity, radioactivity, boiling point, bubble production, and precipitation of the sample.

<h3>Qualitative test for sulfate in alum crystals </h3>

When an aqueous solution of a barium salt (BaCl₂) is mixed with an aqueous solution containing sulfate, a white precipitate of insoluble BaSO₄ forms according to the net ionic equation given below;

Ba²⁺(aq) + SO₄²⁻ (aq)  →   BaSO₄(s)

Thus, a qualitative test for sulfate in alum crystals using ionic reactions of barium chloride (BaCl2) is given Ba²⁺(aq) + SO₄²⁻ (aq)  →   BaSO₄(s).

Learn more about qualitative test here: brainly.com/question/2109763

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8 0
2 years ago
The two isotopes of chlorine are LaTeX: \begin{matrix}35\\17\end{matrix}Cl35 17 C l and LaTeX: \begin{matrix}37\\17\end{matrix}C
Kay [80]

<u>Answer:</u> The percentage abundance of _{17}^{35}\textrm{Cl} and _{17}^{37}\textrm{Cl} isotopes are 77.5% and 22.5% respectively.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

Let the fractional abundance of _{17}^{35}\textrm{Cl} isotope be 'x'. So, fractional abundance of _{17}^{37}\textrm{Cl} isotope will be '1 - x'

  • <u>For _{17}^{35}\textrm{Cl} isotope:</u>

Mass of _{17}^{35}\textrm{Cl} isotope = 35 amu

Fractional abundance of _{17}^{35}\textrm{Cl} isotope = x

  • <u>For _{17}^{37}\textrm{Cl} isotope:</u>

Mass of _{17}^{37}\textrm{Cl} isotope = 37 amu

Fractional abundance of _{17}^{37}\textrm{Cl} isotope = 1 - x

Average atomic mass of chlorine = 35.45 amu

Putting values in equation 1, we get:

35.45=[(35\times x)+(37\times (1-x))]\\\\x=0.775

Percentage abundance of _{17}^{35}\textrm{Cl} isotope = 0.775\times 100=77.5\%

Percentage abundance of _{17}^{37}\textrm{Cl} isotope = (1-0.775)=0.225\times 100=22.5\%

Hence, the percentage abundance of _{17}^{35}\textrm{Cl} and _{17}^{37}\textrm{Cl} isotopes are 77.5% and 22.5% respectively.

6 0
3 years ago
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