(a) 1800 N
The equation of the forces along the vertical direction is:
where
is the component of the applied force along the vertical direction
N is the normal force on the sled
mg is the weight of the sled
Substituting:
F = 1210 N
m = 246 kg
We find N:
(b) 0.580
The equation of the forces along the horizontal direction is:
where
is the horizontal component of the push applied by the mule
is the static frictional force
Substituting:
F = 1210 N
N = 1800 N
We find 
, the coefficient of static friction:
(c) 522 N
In this case, the force exerted by the mule is
So now the equation of the forces along the horizontal direction can be written as
where
and 
is the new frictional force, which is different from part (b) (because the value of the force of friction ranges from zero to the maximum value 
, depending on how much force is applied in the opposite direction)
Solving the equation,
Answer:
approximately 14 billion years ago
Explanation:
brainliest please
Answer:
distance and length are the same quantity
C because of galvination is sized
-- If you're observing the moon from a location in the northern hemisphere, like Canada, Russia, the US, or Israel, then it looks like this picture during the <em>waxing crescent</em> phase.
-- If you're observing the moon from a location in the <u>southern</u> hemisphere, like Australia, South Africa, Paraguay, or Antarctica, then it looks like this picture during the <u>waning</u> crescent phase.
