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NeTakaya
3 years ago
12

Which lengths could be the sides of a triangle?

Mathematics
1 answer:
galina1969 [7]3 years ago
5 0
345,354,354,341,098cm
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Please help me answer this!!
Anna35 [415]

Answer:

Step-by-step explanation:

purple goes to the first

green goes to the third

teal goes to the last

orange goes to second

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B%282x%2B1%29%28x-5%29%7D%7B%28x-5%29%28x%2B4%29%5E%7B2%7D%20%7D" id
dybincka [34]

i) The given function is

f(x)=\frac{(2x+1)(x-5)}{(x-5)(x+4)^2}

The domain is

(x-5)(x+4)^2\ne 0

(x-5)\ne0,(x+4)^2\ne 0

x\ne5,x\ne -4

ii) For vertical asymptotes, we simplify the function to get;

f(x)=\frac{(2x+1)}{(x+4)^2}

The vertical asymptote occurs at

(x+4)^2=0

x=-4

iii) The roots are the x-intercepts of the reduced fraction.

Equate the numerator of the reduced fraction to zero.

2x+1=0

2x=-1

x=-\frac{1}{2}

iv) To find the y-intercept, we substitute x=0 into the reduced fraction.

f(0)=\frac{(2(0)+1)}{(0+4)^2}

f(0)=\frac{(1)}{(4)^2}

f(0)=\frac{1}{16}

v) The horizontal asymptote is given by;

lim_{x\to \infty}\frac{(2x+1)}{(x+4)^2}=0

The horizontal asymptote is y=0.

vi) The function has a hole at x-5=0.

Thus at x=5.

This is the factor common to both the numerator and the denominator.

vii) The function is a proper rational function.

Proper rational functions do not have oblique asymptotes.

6 0
3 years ago
PLZ HURRY IT'S URGENT!!
belka [17]
2y^4 and 5y^4 because same variable (y), same degree (3)
5 0
3 years ago
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Which correctly describes the roots of the following cubic equation x^3-5x^2+3x+9=0?
Bad White [126]

Answer:

C) Three real roots, two of which are equal in value is the right answer I believe.

Step-by-step explanation:


8 0
3 years ago
The measure of angle A is 4 degrees greater than the measure of angle B. The two angles are complementary. Find the measure for
svetlana [45]
Given: 
Angle A is 4 degrees greater than the measure of Angle B. Both angles are complementary

Complementary angles have a sum of 90°

Angle A = x + 4° ; Angle B = x

x + 4° + x = 90°
2x = 90° - 4°
2x = 86°
x = 86° ÷ 2
x = 43° ANGLE B.

Angle A = x + 4° ⇒ 43° + 4 = 47°

Given:
Angle D is 5 times the measure of Angle E. These angles are supplementary. This means that their sum is 180°

Angle D = 5x ; Angle E = x

5x + x = 180°
6x = 180°
x = 180° ÷ 6
x = 30°  Angle E.

Angle D = 5x = 5(30) = 150°
6 0
3 years ago
Read 2 more answers
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