Answer:
i think it's weakest
EDIT: It's net. I answered weakest but it was wrong and the correct answer was net. oops
Explanation:
if a strong force is acting on something it will push it away, meaning the object would go towards the weaker force
Answer:
1.02 m/s²
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 0 m/s
Final velocity (v) = 6.6 m/s
Time (t) = 6.5 s
Acceleration (a) =.?
Acceleration can simply be defined as the change of velocity with time. Mathematically, it can be expressed as:
a = (v – u) / t
Where:
a is the acceleration.
v is the final velocity.
u is the initial velocity.
t is the time.
With the above formula, we can obtain the acceleration of the car as follow:
Initial velocity (u) = 0 m/s
Final velocity (v) = 6.6 m/s
Time (t) = 6.5 s
Acceleration (a) =.?
a = (v – u) / t
a = (6.6 – 0) / 6.5
a = 6.6 / 6.5
a = 1.02 m/s²
Therefore, the acceleration of the car is 1.02 m/s²
Answer:
Explanation:
It is easier to see clothes with pointed needle than a blunt one because pressure exerted is more in a pointed needle as it occupies less space compared to blunt needle, A blunt has more surface area so the pressure exerted will less as compared to a pointed needle.
IF YOU FOUND MY ANSWER USEFUL THEN PLEASE MARK ME BRAINLIEST.
When the capacitor is connected to the voltage, a charge Q is stored on its plates. Calling
the capacitance of the capacitor in air, the charge Q, the capacitance
and the voltage (
) are related by
(1)
when the source is disconnected the charge Q remains on the capacitor.
When the space between the plates is filled with mica, the capacitance of the capacitor increases by a factor 5.4 (the permittivity of the mica compared to that of the air):

this is the new capacitance. Since the charge Q on the plates remains the same, by using eq. (1) we can find the new voltage across the capacitor:

And since
, substituting into the previous equation, we find:

Answer:
Hence, work done= 287.54 J
Explanation:
Given data:
angle of ramp with the ground θ =20°
force applied = 76 N
work done on the crate to slide down 4 m down the ramp
W= F×d cosθ ( only the cos component of the force will slide the crate down)
W= 76×4×cos20= 287.54 J